我正在使用Topshelf创建一个Windows服务(ServiceClass),我正在考虑使用WhenCustomCommandReceived发送自定义命令.
HostFactory.Run(x =>
{
x.EnablePauseAndContinue();
x.Service<ServiceClass>(s =>
{
s.ConstructUsing(name => new ServiceClass(path));
s.WhenStarted(tc => tc.Start());
s.WhenStopped(tc => tc.Stop());
s.WhenPaused(tc => tc.Pause());
s.WhenContinued(tc => tc.Resume());
s.WhenCustomCommandReceived(tc => tc.ExecuteCustomCommand());
});
x.RunAsLocalSystem();
x.SetDescription("Service Name");
x.SetDisplayName("Service Name");
x.SetServiceName("ServiceName");
x.StartAutomatically();
});
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但是,我在WhenCustomCommandReceived行上收到错误:
委托'Action <ServiceClass,HostControl,int>'不带1个参数
签名是
ServiceConfigurator<ServiceClass>.WhenCustomCommandReceived(Action<ServiceClass, HostControl, int> customCommandReceived)
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我已经有了在我的ServiceClass中启动,停止,暂停的方法:public void Start()等.有人能指出我如何设置Action的正确方向吗?谢谢!
因此,正如您在方法的签名中看到的那样,Action需要三个参数,而不仅仅是一个参数.这意味着你需要像这样设置它:
s.WhenCustomCommandReceived((tc,hc,command) => tc.ExecuteCustomCommand());
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在这种情况下,有趣的参数command是类型int.这是发送到服务的命令编号.
您可能希望更改ExecuteCustomCommand方法的签名以接受此类命令:
s.WhenCustomCommandReceived((tc,hc,command) => tc.ExecuteCustomCommand(command));
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并在ServiceClass:
public void ExecuteCustomCommand(int command)
{
//Handle command
}
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这允许您根据收到的命令采取不同的行动.
要测试向服务发送命令(来自另一个C#项目),您可以使用以下代码:
ServiceController sc = new ServiceController("ServiceName"); //ServiceName is the name of the windows service
sc.ExecuteCommand(255); //Send command number 255
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根据此MSDN参考,命令值必须介于128和256之间.
确保在测试项目中引用System.ServiceProcess程序集.
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