用空格替换%20

Question

我有以下功能:

function remove() {
        $value_1 = "Patrick%20Kaka%20M";
        $value_2 = "%";
        $value_3 = " ";
        $new_value = str_replace($value_3, $value_2, $value_1);
        echo 'New value is : ....  '.$new_value.'<br>';
    }

我希望值1输出为Partick Kaka M,但它仍然失败.请告知我如何很好地实施它.

Answer 1

使用 urldecode()

echo urldecode('Patrick%20Kaka%20M');