使用WooCommerce产品搜索搜索特定的post_type表单post_type列时出错

Question

我正在使用此代码从Wordpress/WooCommerce网站搜索产品.
我的要求是URL将像" http:// localhost/wp /？s = D34&post_type = product "同时s=D34是搜索字符串.

当用户搜索字符串时.将从所有默认字段+产品中搜索数据custom filed.下面的代码可以正常使用http:// localhost/wp /？s = D34但是当&post_type=product它与url连接时它会说

代码如下

function cf_search_where( $where ) {
global $pagenow, $wpdb;


    if ( is_search() ) {
$where = preg_replace("/\(\s*".$wpdb->posts.".post_title\s+LIKE\s*(\'[^\']+\')\s*\)/",
            "(".$wpdb->posts.".post_title LIKE $1) OR (".$wpdb->postmeta.".meta_value LIKE $1)", $where );
        $where .= " AND ($wpdb->posts.post_type = 'product') ";
    }

    return $where;
}
add_filter( 'posts_where', 'cf_search_where' );

这是为了防止不同的值

  function cf_search_distinct( $where ) {
        global $wpdb;
if ( is_search() ) {
    return "DISTINCT"; //to prevent duplicates
}

return $where;

}
add_filter( 'posts_distinct', 'cf_search_distinct' );

那么需要进行哪些修改？

URL http:// localhost/wp /？orderby = price&post_type =产品正常工作

但是http:// localhost/wp /？s = D34&post_type = product有什么问题

Answer 1

尝试这个

function cf_search_where( $where ) {
    global $pagenow, $wpdb;

    // a little debugging will help you..
    //print_r ($where);
    //die();

    if ( is_search() ) {

        $where = preg_replace("/\(\s*".$wpdb->posts.".post_title\s+LIKE\s*(\'[^\']+\')\s*\)/",
            "(".$wpdb->posts.".post_title LIKE $1) OR (".$wpdb->postmeta.".meta_value LIKE $1)", $where );
        $where .= " AND ($wpdb->posts.post_type = 'product') ";
    }

    return $where;
}
add_filter( 'posts_where', 'cf_search_where' );

根据您更新的问题。

如果你曾经print_r ($where);检查过值$where包含什么，你会看到类似这样的东西......

与http://localhost/wp/?s=D34

AND (((wp1_posts.post_title LIKE '%D34%') OR (wp1_postmeta.meta_value LIKE '%D34%') OR (wp1_posts.post_content LIKE '%D34%'))) 
AND (wp1_posts.post_password = '') 
AND wp1_posts.post_type IN ('post', 'page', 'attachment', 'product') 
AND (wp1_posts.post_status = 'publish')

与http://localhost/wp/?s=D34&post_type=product

AND (((wp1_posts.post_title LIKE '%D34%') OR (wp1_postmeta.meta_value LIKE '%D34%') OR (wp1_posts.post_content LIKE '%D34%'))) 
AND (wp1_posts.post_password = '') 
AND ( ( wp1_postmeta.meta_key = '_visibility' AND CAST(wp1_postmeta.meta_value AS CHAR) IN ('visible','search') ) ) 
AND wp1_posts.post_type = 'product' 
AND (wp1_posts.post_status = 'publish')

记下wp1_posts.post_type并获得提示..对自己保持灵活性并尝试调试。以上是没有的结果$where .= " AND ($wpdb->posts.post_type = 'product') ";。