react-router - 创建没有组件嵌套的嵌套路由

Question

我有这样的路线配置.

<Route path="group/:groupId" component={NonPropertyView}>
<Route path="group/:groupId/line/:lineId" component={NonPropertyView} />
<Route path="group/:groupId/line/:lineId/property/:propertyId" component={PropertyView} />

但我可以这样做吗？

<Route path="group/:groupId" component={NonPropertyView}>
  <Route path="line/:lineId" component={NonPropertyView}>
    <Route path="property/:propertyId" component={PropertyView} />
  </Route>
</Route>

我正在寻找的是一个选项,只需渲染Component叶子路线而不渲染父路线Component.这可能吗？

Answer 1

是的 - 使用<IndexRoute>s.例如,将上面写为:

<Route path="group/:groupId">
  <IndexRoute component={NonPropertyView} />
  <Route path="line/:lineId">
    <IndexRoute component={NonPropertyView} />
    <Route path="property/:propertyId" component={PropertyView} />
  </Route>
</Route>