如何使用PHP将单个数组项目推送到另一个数组?

Tom*_*lan 4 php arrays

我有一个post调用,它以两种方式之一返回JSON:

$json1 = '{"found":1,"email":"email1@domain.com","error":"","rd":"email2@domain.com"}';
$json2 = '{"found":1,"email":"email1@domain.com,email2@domain.com","error":"","rd":"email3@domain.com,email4@domain.com"}';
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在第一个,emailrd参数每个只有一个电子邮件地址.在第二个中,这两个相同的参数每个都有多个收件人.

我需要从每个参数中获取电子邮件并将其添加到已存在的数组中:

$recipients = array('support@domain.com');
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我可以$json1使用以下代码使用变量:

array_push($recipients, $obj->{'rd'}, $obj->{'email'});
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第二个JSON选项很少发布,但我仍然需要相同的代码才能适用于这两个实例.目前,如果我使用上面的代码与第二个JSON数据,它返回:

Array
(
    [0] => support@sculpturehospitality.com
    [1] => email3@domain.com,email4@domain.com
    [2] => email1@domain.com,email2@domain.com
)
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其中有多个电子邮件在同一个参数中.有没有人对我如何分离每个数组项中的电子邮件有任何见解?

一个工作的例子:

http://sandbox.onlinephpfunctions.com/code/24c4a1eaea98566b65cd36e221dd1f185e820ea6

Riz*_*123 5

只需explode()用逗号表示你的属性并将它们添加到数组中,例如

$recipients = array_merge($recipients, explode(",", $obj->rd)
                                     , explode(",", $obj->email) /*,  ... */);
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还要注意,我现在使用array_merge()而不是array_push(),因为你不再有一个值,而是一个包含新元素的数组:

array_push():

//Single value
$array = ["First element"];
$singleValue = "Second element";

array_push($array, $singleValue);

输出:

Array( [0] => First element [1] => Second element)
//Array
$array = ["First element"];
$secondArray= ["Second element", "And third element"];

array_push($array, $secondArray);

输出:

Array( [0] => First element [1] => Array( [0] => Second element [1] => And third element))

array_merge():

//Single value
$array = ["First element"];
$singleValue = "Second element";

$array = array_merge($array, $singleValue);

输出:

警告:array_merge():参数#2不是数组

//Array
$array = ["First element"];
$secondArray= ["Second element", "And third element"];

$array = array_merge($array, $secondArray);

输出:

Array( [0] => First element [1] => Second element [2] => And third element)