如何在PHP中以DD-MMM-YY格式获取实际日期？

Question

我正在尝试使用DD-MMM-YY格式的php存储实际的sysdate.我想使用该日期在oracle sql server中运行插入.

谢谢

Answer 1

尝试日期功能

date('d-M-y');

这将以此格式返回日期:15-Dec-15(今天).

Answer 2

这很简单。发布前，您必须先用Google搜索。这是完整列表：

<?php
// Assuming today is March 10th, 2001, 5:16:18 pm, and that we are in the
// Mountain Standard Time (MST) Time Zone

$today = date("j-F-Y");                          // 10-March-2001
$today = date("F j, Y, g:i a");                 // March 10, 2001, 5:16 pm
$today = date("m.d.y");                         // 03.10.01
$today = date("j, n, Y");                       // 10, 3, 2001
$today = date("Ymd");                           // 20010310
$today = date('h-i-s, j-m-y, it is w Day');     // 05-16-18, 10-03-01, 1631 1618 6 Satpm01
$today = date('\i\t \i\s \t\h\e jS \d\a\y.');   // it is the 10th day.
$today = date("D M j G:i:s T Y");               // Sat Mar 10 17:16:18 MST 2001
$today = date('H:m:s \m \i\s\ \m\o\n\t\h');     // 17:03:18 m is month
$today = date("H:i:s");                         // 17:16:18
?>

参考