只有CSS发生变化时,Gulp livereload会重新加载整个页面

Question

我已经将livereload添加到了我的Gulp任务中.它的工作除了我编辑CSS文件时整个页面都被刷新,而不仅仅是页面CSS.

 var gulp = require('gulp');
 var uglify = require('gulp-uglify');
 var concat = require('gulp-concat');
 var minifyCss = require('gulp-minify-css');
 var sizereport = require('gulp-sizereport');
 var watch = require('gulp-watch');
 var batch = require('gulp-batch');
 var run = require('run-sequence');

gulp.task('watch-theme-css', ['theme-css'], function () {
  livereload.listen();
  watch(themeFiles.sass, batch(function (events, done) {
    gulp.start('theme-css', done);
  }))
});

var themeFiles = {
  sass: [
    'mysite/base/sass/*.s+(a|c)ss',
    'mysite/content/sass/*.s+(a|c)ss',
    'mysite/custom/sass/*.s+(a|c)ss'
  ],
  out: {
    css: 'mysite/build'
  }
};

gulp.task('theme-css', function () {
  return gulp.src(themeFiles.sass)
    .pipe(gulpif(env === 'development', sourcemaps.init()))
    .pipe(sass().on('error', sass.logError))
    .pipe(minifyCss({
      compatibility: 'ie8'
    }))
    .pipe(gulpif(env === 'dev', sourcemaps.write('.')))
    .pipe(gulp.dest(themeFiles.out.css))
    .pipe(livereload());
});

更新我已经从下面的链接尝试了以下代码,但它做了同样的事情.http://www.roelvanlisdonk.nl/?p=4675

gulp.task('watch-theme-css', ['theme-css'], function () {
  livereload.listen();
  watch(themeFiles.sass, batch(function (events, done) {
    gulp.start('theme-css', done);
  }), ["reloadCss"]);
});

与此相同的行为:https://laracasts.com/discuss/channels/tips/proper-way-to-use-livereload-with-laravel-elixir

gulp.task('watch-lr-css', ['theme-css'], function () {
  livereload.changed(themeFiles.sass);
});

我试过以下但是当我尝试打开实时重新加载浏览器插件时,它说它无法找到实时重装服务器. gulp:如何在不刷新的情况下更新浏览器(仅适用于css更改)

gulp.task('watch-theme-css', ['theme-css'], function () {
  //livereload.listen();
  livereload.changed(themeFiles.sass);
  watch(themeFiles.sass, batch(function (events, done) {
    gulp.start('theme-css', done);
  }));
});

Answer 1

我昨晚花了几个小时来看看这个:https://github.com/vohof/gulp-livereload/issues/93.

看起来是因为你的源图.gulp-livereload试图变得聪明,如果只有css更改,则只重新加载css.否则它会重新加载整个页面,因为它认为有更多的文件发生了变化.

所以你只需要在调用livereload()函数之前将你的glob过滤到只有css .

所以这样的事情可能有所帮助:

var filter = require('gulp-filter');

...

gulp.task('theme-css', function () {
  return gulp.src(themeFiles.sass)
    .pipe(gulpif(env === 'development', sourcemaps.init()))
    .pipe(sass().on('error', sass.logError))
    .pipe(minifyCss({
      compatibility: 'ie8'
    }))
    .pipe(gulpif(env === 'dev', sourcemaps.write('.')))
    .pipe(gulp.dest(themeFiles.out.css))

    // Add filter here
    .pipe(filter('**/*.css'))
    .pipe(livereload());
});

Answer 2

livereload.changed(files)发生变化时您需要打电话。为此，请参阅 gulp-watch 文档。

watch('**/*.js', function (files) {
  livereload.changed(files)
});