使用Graph API获取我朋友的朋友

Question

我正在尝试使用新的Graph API做一个非常基本的事情.

我已经知道如何找到我的朋友:" https://graph.facebook.com/me/friends?access_token=4333ed34d ......"

但如果我的朋友的身份证号码是123456,那么我想得到他的朋友:" https://graph.facebook.com/123456/friends?access_token=4333ed34d ......"

但我得到一个例外:

"远程服务器返回错误:(500)内部服务器错误."

为什么我不能这样做？从API中提问是一项非常简单的任务.

Answer 1

如果我试图获得随机用户的朋友,我会获得HTTP 500,但它包含此响应:

{
   "error": {
      "type": "Exception",
      "message": "(#604) Can't lookup all friends of <UID>. Can only lookup for the logged in user (<MY_UID>), or friends of the logged in user with the appropriate permission"
   }
}

这是非常明显的.

如果我试图找到我的朋友的朋友,他允许查看他的其他朋友,它工作正常.如果我的朋友选择不允许查看他的其他朋友,我会得到同样的错误.

Answer 2

你可以从公共Facebook窃取信息.它不漂亮,需要几秒钟,但有效.

我有一个从控制台运行的JS代码并发出AJAX请求 - 当你向下滚动时,在常规facebook UI中请求更多朋友时,facebook会做同样的事情(http://www.facebook.com/profile.php?sk=friends) .然后我解析结果.到目前为止,它完美无缺.我只是想要更多的朋友,当我没有得到比赛时,我知道我拥有所有这些.

我不想分享整个代码,但这是必不可少的部分:

// Recursively load person friends 
function getMoreFriends(job, uid, fb_dtsg, post_form_id, offset, callback, finished ){
    var url = "http://www.facebook.com/ajax/browser/list/friends/all/?uid="+uid+"&offset="+offset+"&dual=1&__a=1&fb_dtsg="+fb_dtsg+"&lsd=&post_form_id="+post_form_id+"&post_form_id_source=AsyncRequest";  
    var request = { type: 'POST', url: url, data: { __a: 1, dual: 1, offset: offset, uid: uid }, dataType: "text", complete: function(data){
    var response = data.responseText.match(/HTML.*$/)[0];
        response = response.replace(/u003c/gi,"<");
        response = response.replace(/\\u([a-f0-9]{4})/gm, "&#x$1;").replace(/\\\//g,"/").replace(/\\/g,'');
        response = response.match(/^.*<\/div><\/div><\/div>/);
        if(response != null){
            response = response[0].replace("HTML(","");
            var people = [];
        $jq(response).find(".UIImageBlock").each( function(){
            var newPerson = new Person( $jq(this).find('.UIImageBlock_Content a').text(), $jq(this).find('a').first().attr('href'), $jq(this).find('img').attr('src'), jQuery.parseJSON( $jq(this).find('a').last().attr('data-gt') ).engagement.eng_tid );
            people.push( newPerson );
            });
            callback(people);
            getMoreFriends(job, uid, fb_dtsg, post_form_id, offset+60, callback, finished);
        }
    } };
    job.addToQueue( request );
    if(job.state != "processing"){
        if (typeof finished != "function" ){ finished = function(){}; }
        job.startProcessing({ finished: function(){ finished(); } } );
    }
}

您可以从当前登录的用户获取必要的变量,如下所示:

function loadFriends(person, onInit, store, callback){
    info("loading friends of "+person.name+" initiated");
    //addStatus("loading friends of "+person.name+" initiated");

    if (typeof onInit == "function" ){
        onInit();
    }

    if(person.id == -1){
        error("Person "+person.name+" doesn't have an id.!");
        addStatus("Person "+person.name+" doesn't have an id.!","error");
        return false;
    }
    else {
        // Load friends 
        var fb_dtsg = $jq('input[name="fb_dtsg"]').eq(0).val();
        var post_form_id = $jq('#post_form_id').val();
        var loadFriendsJob = ajaxManager.addJob({limit: 1});
        getMoreFriends(loadFriendsJob,person.id, fb_dtsg, post_form_id, 0,     function(people){ // callback on each iteration
            d( "Loaded "+people.length+" friends of " + person.name );
            store(people);
        },function(){ // callback on finish
            info("loading friends of "+person.name+" finished");
            //addStatus("loading friends of "+person.name+" finished");
            if (typeof callback == "function" ){ callback(); }
        });
    }

}

我知道这可能对你的情况毫无用处,因为这是JS.无论如何,有人可能会觉得这很有用.

PS:$ jq = jQuery.PPS:这些作业对象负责顺序的ajax请求.我发现我需要它们,因为我的FF不想同时发出2000+ AJAX请求:-D