可以说我有物品
items : [{id:1,...}, {id:2,...}, {id:3,...}]
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并命令:[ 2,3,1 ]得到一个可枚举的
items : [{id:2,...}, {id:3,...}, {id:1,...}]
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我希望它能成为符合标准的东西
items.Select(o => new {key = ordering[i++], value = o})
.OrderBy(k => k.key)
.Select(o => o.value)
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但有更清洁的解决方案吗?
以下我已经确认了这项工作(HimBromBeere,Domysee,qxg)
var expectedOrder = ordering.Select(x => result.First(o => o.Id == x));
var expectedOrder = result.OrderBy(item => Array.FindIndex(ordering,i => i == item.Id));
var expectedOrder = result.OrderBy(item => ordering.ToList().FindIndex(i => i == item.Id));
var expectedOrder =
from o in ordering
join i in result
on o equals i.Id
select i;
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Fwi,这是用于验证测试:
[Test]
[TestCase(1, 2, 3)]
[TestCase(1, 3, 2)]
[TestCase(2, 1, 3)]
[TestCase(2, 3, 1)]
[TestCase(3, 1, 2)]
public void Test_Should_Fail_If_GetMessages_Does_Not_Return_Sorted_By_Sent_Then_By_Id_Result(params int[] ordering)
{
var questions = GetQuestionsData();
Mock.Get(_questionService)
.Setup(o => o.GetQuestions())
.Returns(questions);
var result = _mailboxService.GetMessages();
var expectedOrder = ordering.Select(x => result.First(o => o.Id == x));
// Act
Action sortOrder = () => expectedOrder.Should()
.BeInDescendingOrder(o => o.Sent)
.And.BeInDescendingOrder(o => o.Id);
// Assert
sortOrder.ShouldThrow<AssertionException>();
}
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我猜是这样的:
var result = ordering.Select(x => items.First(y => y.id == x.id));
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工作示例:
var items = new[] { new { id = 1, name = "1" }, new { id = 2, name = "2" }, new { id = 3, name = "3" }, new { id = 4, name = "4" } };
var result = new[] { 2, 3, 1 }.Select(x => items.First(y => y.id == x));
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这也会过滤items掉那些索引不包含在 中的索引ordering。