在ggplot2中的地图上围绕点绘制具有特定半径的圆

Question

我有一张地图,上面画着8个点:

library(ggplot2)
library(ggmap)
data = data.frame(
    ID = as.numeric(c(1:8)),
    longitude = as.numeric(c(-63.27462, -63.26499, -63.25658, -63.2519, -63.2311, -63.2175, -63.23623, -63.25958)),
    latitude = as.numeric(c(17.6328, 17.64614, 17.64755, 17.64632, 17.64888, 17.63113, 17.61252, 17.62463))
)

island = get_map(location = c(lon = -63.247593, lat = 17.631598), zoom = 13, maptype = "satellite")
islandMap = ggmap(island, extent = "panel", legend = "bottomright")
RL = geom_point(aes(x = longitude, y = latitude), data = data, color = "#ff0000")
islandMap + RL + scale_x_continuous(limits = c(-63.280, -63.21), expand = c(0, 0)) + scale_y_continuous(limits = c(17.605, 17.66), expand = c(0, 0))

现在我想围绕8个绘制位置绘制一个圆圈.圆的半径必须为450米.

这就是我的意思,但随后使用ggplot:https://gis.stackexchange.com/questions/119736/ggmap-create-circle-symbol-where-radius-represents-distance-miles-or-km

我怎样才能做到这一点？

Answer 1

如果你只在地球的一个小区域工作,这里是近似值.每个纬度都代表40075/360公里.每个经度表示(40075/360)*cos(纬度)千米.有了这个,我们可以计算大约一个数据框,包括圆上的所有点,知道圆心和半径.

library(ggplot2)
library(ggmap)
data = data.frame(
    ID = as.numeric(c(1:8)),
    longitude = as.numeric(c(-63.27462, -63.26499, -63.25658, -63.2519, -63.2311, -63.2175, -63.23623, -63.25958)),
    latitude = as.numeric(c(17.6328, 17.64614, 17.64755, 17.64632, 17.64888, 17.63113, 17.61252, 17.62463))
)

#################################################################################
# create circles data frame from the centers data frame
make_circles <- function(centers, radius, nPoints = 100){
    # centers: the data frame of centers with ID
    # radius: radius measured in kilometer
    #
    meanLat <- mean(centers$latitude)
    # length per longitude changes with lattitude, so need correction
    radiusLon <- radius /111 / cos(meanLat/57.3) 
    radiusLat <- radius / 111
    circleDF <- data.frame(ID = rep(centers$ID, each = nPoints))
    angle <- seq(0,2*pi,length.out = nPoints)

    circleDF$lon <- unlist(lapply(centers$longitude, function(x) x + radiusLon * cos(angle)))
    circleDF$lat <- unlist(lapply(centers$latitude, function(x) x + radiusLat * sin(angle)))
    return(circleDF)
}

# here is the data frame for all circles
myCircles <- make_circles(data, 0.45)
##################################################################################


island = get_map(location = c(lon = -63.247593, lat = 17.631598), zoom = 13, maptype = "satellite")
islandMap = ggmap(island, extent = "panel", legend = "bottomright")
RL = geom_point(aes(x = longitude, y = latitude), data = data, color = "#ff0000")
islandMap + RL + 
    scale_x_continuous(limits = c(-63.280, -63.21), expand = c(0, 0)) + 
    scale_y_continuous(limits = c(17.605, 17.66), expand = c(0, 0)) +
    ########### add circles
    geom_polygon(data = myCircles, aes(lon, lat, group = ID), color = "red", alpha = 0)

Answer 2

好吧,正如推荐的帖子已经暗示的那样 - 切换到以米为单位的投影,然后返回:

library(rgeos)
library(sp)
d <- SpatialPointsDataFrame(coords = data[, -1], 
                            data = data, 
                            proj4string = CRS("+init=epsg:4326"))
d_mrc <- spTransform(d, CRS("+proj=merc +a=6378137 +b=6378137 +lat_ts=0.0 +lon_0=0.0 +x_0=0.0 +y_0=0 +k=1.0 +units=m +nadgrids=@null +no_defs"))

现在,width可以用米来指定:

d_mrc_bff_mrc <- gBuffer(d_mrc, byid = TRUE, width = 450)

将其转换回来并使用geom_path以下方法将其添加到绘图中:

d_mrc_bff <- spTransform(d_mrc_bff_mrc, CRS("+init=epsg:4326"))
d_mrc_bff_fort <- fortify(d_mrc_bff)
islandMap + 
  RL + 
  geom_path(data=d_mrc_bff_fort, aes(long, lat, group=group), color="red") + 
  scale_x_continuous(limits = c(-63.280, -63.21), expand = c(0, 0)) + 
  scale_y_continuous(limits = c(17.605, 17.66), expand = c(0, 0)) 

Answer 3

在给定纬度和经度的情况下计算以公里为单位的距离并不是非常简单；例如，1 度纬度/经度在赤道处的距离比在两极处的距离大。如果您想要一个简单的解决方法，可以观察准确性，您可以尝试：

islandMap + RL + 
  scale_x_continuous(limits = c(-63.280, -63.21), expand = c(0, 0)) + 
  scale_y_continuous(limits = c(17.605, 17.66), expand = c(0, 0)) + 
  geom_point(aes(x = longitude, y = latitude), data = data, size = 20, shape = 1,  color = "#ff0000")

您需要调整size第二个参数geom_point以更接近您想要的。我希望这有帮助！