引起:java.sql.SQLException:未找到列“id”

que*_*nto 5 java sql entity hibernate

我想获取一些字段,然后将其设置为我的 Test.entity。我的 SQL 查询:

                query = "SELECT t.id as tId, t.test_name, t.duration, q.id as qId, " +
                    "q.question as question, q.is_multichoice as is_multichoice, " +
                    "q.is_open as is_open, a.id as aId, a.answer_text as answer_text  FROM result r " +
                    "JOIN test t ON r.test_id = t.id " +
                    "JOIN user u ON r.user_id = u.id " +
                    "JOIN question q ON t.id = q.test_id JOIN answer a ON q.id = a.question_id " +
                    "WHERE t.id = :testId AND u.id = :userId AND r.permission = :permissionId " +
                    "AND q.archived = false AND a.archived = false", resultClass = com.bionic.entities.Test.class)
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测试实体:

public class Test {
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@Column(name = "duration", nullable = false)
private int duration;
@Column(name = "test_name", nullable = false, unique = true)
private String testName;
@Column(name = "archived", nullable = false)
private boolean archived;
@OneToMany(mappedBy = "test", fetch = FetchType.EAGER)
private Set<Question> questions;
@ManyToMany(mappedBy = "tests")
private Set<User> users;
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问题实体

public class Question {
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@Column(name = "is_multichoice", nullable = false)
private boolean isMultichoice;
@Column(name = "is_open", nullable = false)
private boolean isOpen;
@Column(name = "picture")
private String picture;
@Column(name = "question")
private String question;
@ManyToOne
@JoinColumn(name = "test_id", nullable = false)
private Test test;
@Column(name = "archived", nullable = false)
private boolean isArchived;
@OneToMany(mappedBy = "question", fetch = FetchType.EAGER)
private Set<Answer> answers;
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回答实体:

public class Answer {
@Id
@Column(name = "id")
@GeneratedValue(strategy = GenerationType.AUTO)
private long id;
@Column(name = "answer_text", nullable = false)
private String answerText;
@Column(name = "mark", nullable = false)
private int mark;
@ManyToOne
@JoinColumn(name = "question_id")
private Question question;
@Column(name = "picture")
private String picture;
@Column(name = "archived", nullable = false)
private boolean isArchived;
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但是,在执行此查询后,我得到了例外:

Caused by: java.sql.SQLException: Column 'id' not found.
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DAO.class:

    public Test getCurrentTest(long id, long testId, long permissionId) {
    Query query = em.createNamedQuery("getCurrentTestById");
    query.setParameter("userId", id);
    query.setParameter("testId", testId);
    query.setParameter("permissionId", permissionId);
    return (Test) query.getSingleResult();
}
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我究竟做错了什么?

Rab*_*bit 8

您的查询不会返回名为 的字段id。它有名为 的字段aId, qId, and tId

您需要在实体中使用正确的列名称。例如,在您的 Test 实体中,您声明了一个名为 id 的列。除了您的查询不返回名为 id 的列,它返回名为 tId 的列。有关需要更改的内容的示例,请参见下文。

public class Test {
@tId
@Column(name = "tId")
@GeneratedValue(strategy = GenerationType.AUTO)
private long tId;
 .... 
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