PHP从函数中获取变量

Question

function first() {
    foreach($list as $item ) {
        ${'variable_' . $item->ID} = $item->title;
        // gives $varible_10 = 'some text'; (10 can be replaced with any number)
    }
    $ordinary_variable = 'something';
}

如何在另一个函数中获取此函数的值？

喜欢:

function second() {
    foreach($list as $item ) {
        get ${'variable_' . $item->ID};
        // getting identical value from first() function
    }
    get $ordinary_variable;
}

• 我们知道$variable_id(id是数字)已经存在于first()
• $list是一个Array(),可以有超过100个值.
• $ordinary_variable 是一个字符串.

谢谢.

Answer 1

你可以让第一个函数返回一个数组:

function first() {
    $values = array();
    foreach($list as $item ) {
        $values['variable_' . $item->ID] = $item->title;
        // gives $varible_10 = 'some text'; (10 can be replaced with any number)
    }
    $values['ordinary_variable'] = 'something';
    return $values;
}

然后:

function second() {
    $values = first();
    foreach($list as $item ) {
        $values['variable_' . $item->ID];
        // getting identical value from first() function
    }
    $values['ordinary_variable'];
}

或将其作为参数传递:

second(first());

我建议反对,global因为这会引入副作用并使代码更难维护/调试.