Jav*_*tar 8 java hibernate jpa persistence-unit ejb-3.0
在使用struts2 ejb hibernate的Web应用程序中,是否可以告诉应用程序persistence.xml在部署时间内查找或创建特定持久性单元名称的实体,该实体是在文件中写入的?
我persistence.xml在jboss节点下有两个持久性单元和一个数据源(包括两个"local-tx-datasource")xml文件.
为了清楚,我的意思是,我试过这个;
@Entity
@PersistenceContext(unitName="MY JNDI NAME specified in persistence.xml")
public abstract class Vehicle {
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并没有工作..然后尝试了这等等..
@PersistenceContext(name="MY PERSISTENCE UNIT NAME specified in persistence.xml")
@PersistenceUnit(name="MY PERSISTENCE UNIT NAME specified in persistence.xml")
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而且我用"UnitName = .."而不是"name = .."尝试了上面这些,但是任何东西都适用于我......
[解决了]
<.exclude-unlisted-classes> true <./ exclude-unlisted-classes>解决了我的问题
更新:根据您的评论(这不是我从原始问题中理解的),我认为除了禁用"发现"并在各自的持久性单元中明确列出您的实体之外,您没有任何其他选择:
<?xml version="1.0" encoding="UTF-8"?>
<persistence
xmlns="http://java.sun.com/xml/ns/persistence"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd"
version="2.0">
<persistence-unit name="MyPu1" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.mycompany.Foo</class>
...
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<!-- H2 in memory -->
<property name="javax.persistence.jdbc.driver" value="org.h2.Driver"/>
<property name="javax.persistence.jdbc.url" value="jdbc:h2:mem:test"/>
<property name="javax.persistence.jdbc.username" value="APP"/>
<property name="javax.persistence.jdbc.password" value="APP"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
</properties>
</persistence-unit>
<persistence-unit name="MyPu2" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<class>com.mycompany.Bar</class>
...
<exclude-unlisted-classes>true</exclude-unlisted-classes>
<properties>
<!-- Derby server -->
<property name="javax.persistence.jdbc.driver" value="org.apache.derby.jdbc.ClientDriver"/>
<property name="javax.persistence.jdbc.user" value="APP"/>
<property name="javax.persistence.jdbc.password" value="APP"/>
<property name="javax.persistence.jdbc.url" value="jdbc:derby://localhost:1527/Pu2;create=true"/>
<property name="hibernate.hbm2ddl.auto" value="update"/>
</properties>
</persistence-unit>
</persistence>
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我不知道实体级别的任何语法允许将其分配给持久性单元.
我不确定我理解你要做什么,但是如果你想为注入的特定持久性单元获得实体管理器,你应该这样做:
@Stateless
public class FooBean implements Foo {
@PersistenceContext(unitName="MyPu1")
EntityManager em1;
// ...
}
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如果这不是您想要的,请澄清问题.