Séb*_*rra 21 ruby language-agnostic scheme continuations smalltalk
我正在努力掌握延续的概念,我在维基百科的文章中找到了几个像这样的小教学例子:
(define the-continuation #f)
(define (test)
(let ((i 0))
; call/cc calls its first function argument, passing
; a continuation variable representing this point in
; the program as the argument to that function.
;
; In this case, the function argument assigns that
; continuation to the variable the-continuation.
;
(call/cc (lambda (k) (set! the-continuation k)))
;
; The next time the-continuation is called, we start here.
(set! i (+ i 1))
i))
Run Code Online (Sandbox Code Playgroud)
我理解这个小函数的作用,但是我看不出任何明显的应用.虽然我不希望很快在我的代码中使用延续,但我希望我知道一些它们可能适合的情况.
所以我正在寻找更多有用的代码示例,这些代码示例可以为程序员提供什么延续.
干杯!
sve*_*ven 16
在Algo和Data II中,我们一直使用这些来从(长)函数"退出"或"返回"
例如,用于遍历树的BFS算法实现如下:
(define (BFS graph root-discovered node-discovered edge-discovered edge-bumped . nodes)
(define visited (make-vector (graph.order graph) #f))
(define q (queue.new))
(define exit ())
(define (BFS-tree node)
(if (node-discovered node)
(exit node))
(graph.map-edges
graph
node
(lambda (node2)
(cond ((not (vector-ref visited node2))
(when (edge-discovered node node2)
(vector-set! visited node2 #t)
(queue.enqueue! q node2)))
(else
(edge-bumped node node2)))))
(if (not (queue.empty? q))
(BFS-tree (queue.serve! q))))
(call-with-current-continuation
(lambda (my-future)
(set! exit my-future)
(cond ((null? nodes)
(graph.map-nodes
graph
(lambda (node)
(when (not (vector-ref visited node))
(vector-set! visited node #t)
(root-discovered node)
(BFS-tree node)))))
(else
(let loop-nodes
((node-list (car nodes)))
(vector-set! visited (car node-list) #t)
(root-discovered (car node-list))
(BFS-tree (car node-list))
(if (not (null? (cdr node-list)))
(loop-nodes (cdr node-list)))))))))
Run Code Online (Sandbox Code Playgroud)
如您所见,当节点发现的函数返回true时,算法将退出:
(if (node-discovered node)
(exit node))
Run Code Online (Sandbox Code Playgroud)
该函数还将给出"返回值":'node'
为什么函数退出,是因为这句话:
(call-with-current-continuation
(lambda (my-future)
(set! exit my-future)
Run Code Online (Sandbox Code Playgroud)
当我们使用exit时,它将返回执行前的状态,清空调用堆栈并返回你给它的值.
基本上,call-cc用于(这里)跳出递归函数,而不是等待整个递归自行结束(在进行大量计算工作时这可能非常昂贵)
另一个与call-cc做同样的小例子:
(define (connected? g node1 node2)
(define visited (make-vector (graph.order g) #f))
(define return ())
(define (connected-rec x y)
(if (eq? x y)
(return #t))
(vector-set! visited x #t)
(graph.map-edges g
x
(lambda (t)
(if (not (vector-ref visited t))
(connected-rec t y)))))
(call-with-current-continuation
(lambda (future)
(set! return future)
(connected-rec node1 node2)
(return #f))))
Run Code Online (Sandbox Code Playgroud)
@拍
海滨
是的,Seaside就是一个很好的例子.我快速浏览了它的代码,发现这条消息说明了在Web上以一种看似有状态的方式在组件之间传递控制.
WAComponent >> call: aComponent
"Pass control from the receiver to aComponent. The receiver will be
temporarily replaced with aComponent. Code can return from here later
on by sending #answer: to aComponent."
^ AnswerContinuation currentDo: [ :cc |
self show: aComponent onAnswer: cc.
WARenderNotification raiseSignal ]
Run Code Online (Sandbox Code Playgroud)
很好!
我建立了自己的单元测试软件.在执行测试之前,我在执行测试之前存储延续,然后在失败时,我(可选)告诉方案解释器进入调试模式,并重新调用延续.这样我就可以轻松地逐步完成有问题的代码.
如果您的continuation是可序列化的,那么您还可以存储应用程序失败,然后重新调用它们以获取有关变量值,堆栈跟踪等的详细信息.
某些Web服务器和Web框架使用Continuations来存储会话信息.为每个会话创建一个continuation对象,然后由会话中的每个请求使用.
我来到了防空火炮的实现,amb运营商在这个职位从http://www.randomhacks.net,使用延续.
这是操作amb员的作用:
# amb will (appear to) choose values
# for x and y that prevent future
# trouble.
x = amb 1, 2, 3
y = amb 4, 5, 6
# Ooops! If x*y isn't 8, amb would
# get angry. You wouldn't like
# amb when it's angry.
amb if x*y != 8
# Sure enough, x is 2 and y is 4.
puts x, y
Run Code Online (Sandbox Code Playgroud)
这是帖子的实现:
# A list of places we can "rewind" to
# if we encounter amb with no
# arguments.
$backtrack_points = []
# Rewind to our most recent backtrack
# point.
def backtrack
if $backtrack_points.empty?
raise "Can't backtrack"
else
$backtrack_points.pop.call
end
end
# Recursive implementation of the
# amb operator.
def amb *choices
# Fail if we have no arguments.
backtrack if choices.empty?
callcc {|cc|
# cc contains the "current
# continuation". When called,
# it will make the program
# rewind to the end of this block.
$backtrack_points.push cc
# Return our first argument.
return choices[0]
}
# We only get here if we backtrack
# using the stored value of cc,
# above. We call amb recursively
# with the arguments we didn't use.
amb *choices[1...choices.length]
end
# Backtracking beyond a call to cut
# is strictly forbidden.
def cut
$backtrack_points = []
end
Run Code Online (Sandbox Code Playgroud)
我喜欢amb!