按第一个元素分组数组

Le *_*ang 1 scala scala-collections

我有一个这样的数组[(Int,(Int,Int))],

   (24, (12, 5))
   (12, (17, 3))
   (1,  (7, 25))
   (24, (4, 6))
   (1,  (13, 3))
   (12, (9, 14))
   (24, (9, 18))
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我想用第一个元素对这些数组进行分组,这意味着我希望:

   (24, ((12, 5), (4, 6), (9, 18)))
   (12, ((17, 3), (9, 14)))
   (1,  ((7, 25), (13, 3)))  
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谁能帮我这个?

Nya*_*vro 7

所以你有了:

val arr = Array((24, (12, 5)), (12, (17, 3)), (1,  (7, 25)), (24, (4, 6)), (1,  (13, 3)), (12, (9, 14)), (24, (9, 18)))
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您可以使用组方法进行分组:

val grouped = arr.groupBy(_._1).map {case (k,v) => k -> v.map {case (_, (b,c))=> (b,c)}}
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要么:

val grouped = arr.groupBy(_._1).mapValues {_.map {case (_, (b,c))=> (b,c)}}
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