sca*_*cci 5 xml sql t-sql sql-server sql-server-2008
我有两个单独的表TV和Receivers,我使用FOR XML PATH命令来构建XML.我的问题是我想将TV XML Build的输出与我的Receiver XML Build结合起来创建一个XML输出.
所以我会有这样的东西(这使我能够在FilterData Root中保持电视和接收器标签分开):
<FilterData>
<TVs>
<TV>
<Type>LCD</Type>
<Brand>Samsung</Brand>
</TV>
<TV>
<Type>LCD</Type>
<Brand>Panasonic</Brand>
</TV>
</TVs>
<Receivers>
<Receiver>
<Type>Surround 7.1</Type>
<Brand>Onkyo</Brand>
</Receiver>
<Receiver>
<Type>Surround 7.1</Type>
<Brand>Denon</Brand>
</Receiver>
</Receivers>
</FilterData>
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问题是当我构建我的查询以输出这个XML时
Select
Type
,Brand
From dbo.TVs
FOR XML PATH('TV'),ROOT('TVS') TYPE
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和
Select
Type
,Brand
From dbo.Receivers
FOR XML PATH('Receiver'),ROOT('Receivers') TYPE
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我不知道如何将这些结合起来看起来像一个例子:
<FilterData>
<TVs>
<TV>
<Type>LCD</Type>
<Brand>Samsung</Brand>
</TV>
<TV>
<Type>LCD</Type>
<Brand>Panasonic</Brand>
</TV>
</TVs>
<Receivers>
<Receiver>
<Type>Surround 7.1</Type>
<Brand>Onkyo</Brand>
</Receiver>
<Receiver>
<Type>Surround 7.1</Type>
<Brand>Denon</Brand>
</Receiver>
</Receivers>
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使用:
SELECT (SELECT t.type, t.brand
FROM dbo.TVs t
FOR XML PATH('tv'), ROOT('tvs'), ELEMENTS, TYPE),
(SELECT r.type, r.brand
FROM dbo.Receivers r
FOR XML PATH('receiver'), ROOT('receivers'), ELEMENTS, TYPE)
FOR XML PATH('filterdata')
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测试使用:
WITH tvs AS (
SELECT 'LCD' AS type, 'Samsung' AS brand
UNION ALL
SELECT 'LCD' AS type, 'Panasonic' AS brand),
receivers AS (
SELECT 'Surround 7.1' AS type, 'Onkyo' AS brand
UNION ALL
SELECT 'Surround 7.1', 'Denon')
SELECT (SELECT t.type, t.brand
FROM tvs t
FOR XML PATH('tv'), ROOT('tvs'), ELEMENTS, TYPE),
(SELECT r.type, r.brand
FROM receivers r
FOR XML PATH('receiver'), ROOT('receivers'), ELEMENTS, TYPE)
FOR XML PATH('filterdata')
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