duk*_*vin 8 c# arrays string list
我想在编译时填充字符串数组的List
这样的事情:
List<string[]> synonyms = new List<string[]>
{
{ "enabled", "enable", "enabling" },
{ "disabled", "disable", "disabling" },
{ "s0", "s0 state" },
{ "s5", "s5 state" }
};
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但我得到一个编译错误:
No overloaded method 'Add' takes 2 arguments
为什么是这样?如果它们不是字符串数组,它就可以工作List<string>
您没有在示例中创建数组,请尝试以下操作:
List<string[]> synonyms = new List<string[]>
{
new[] { "enabled", "enable", "enabling" },
new[] { "disabled", "disable", "disabling" },
new[] { "s0", "s0 state" },
new[] { "s5", "s5 state" }
};
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您需要添加一个字符串数组
List<string[]> synonyms = new List<string[]>
{
new string[] { "enabled", "enable", "enabling" },
new string[] { "disabled", "disable", "disabling" },
new string[] { "s0", "s0 state" },
new string[] { "s5", "s5 state" }
};
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为List
初始化程序创建隐式类型数组:
List<string[]> synonyms = new List<string[]>
{
new [] { "enabled", "enable", "enabling" },
new [] { "disabled", "disable", "disabling" },
new [] { "s0", "s0 state" },
new [] { "s5", "s5 state" }
};
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new [] { ... }
相当于new string[] { ... }
当数组中的对象类型都是时string
.如果数组中对象的类型不同,您将使用隐式语法获得错误.
究其原因,你的代码并没有工作在阐述了如何:初始化字典与集合初始化器(C#编程指南):
字典包含键/值对的集合.它的Add方法有两个参数,一个用于键,一个用于值.要初始化Dictionary 或Add方法采用多个参数的任何集合,请将每组参数括在大括号中...
因此,在语法中
{
{ "enabled", "enable", "enabling" },
}
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编译器期望您的集合有一个Add(string, string, string)
方法.因为没有这样的方法List<string []>
,所以编译失败.
实际上,可以使用这种语法创建这样的集合并对其进行初始化.如果您创建以下集合:
public class TripleCollection<T> : IEnumerable<Tuple<T, T, T>>
{
readonly List<Tuple<T, T, T>> list = new List<Tuple<T, T, T>>();
public void Add(T first, T second, T third)
{
list.Add(Tuple.Create(first, second, third));
}
public IEnumerator<Tuple<T, T, T>> GetEnumerator()
{
return list.GetEnumerator();
}
System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
{
return GetEnumerator();
}
}
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以下将成功编译并创建一个包含一个3元组的集合:
var tuples = new TripleCollection<string>
{
{ "1", "2", "3" },
};
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您还可以创建以下List
子类:
public class ListOfArray<T> : List<T[]>
{
public new void Add(params T[] args)
{
base.Add(args);
}
}
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并使用所需的语法初始化它:
var synonyms = new ListOfArray<string>
{
{ "enabled", "enable", "enabling" },
{ "disabled", "disable", "disabling" },
{ "s0", "s0 state" },
{ "s5", "s5 state" }
};
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但List<string []>
正如其他人所指出的那样,您需要通过显式分配每个string []
条目来初始化您的同义词列表,而不是为每个条目使用隐式集合intializer:
var synonyms = new List<string[]>
{
new [] { "enabled", "enable", "enabling" },
new [] { "disabled", "disable", "disabling" },
new [] { "s0", "s0 state" },
new [] { "s5", "s5 state" }
};
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您需要指定内部对象是数组,以便它不会查找多参数Add方法.
List<string[]> synonyms = new List<string[]>
{
new[] { "enabled", "enable", "enabling" },
new[] { "disabled", "disable", "disabling" },
new[] { "s0", "s0 state" },
new[] { "s5", "s5 state" }
};
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