AP3*_*P30 2 variables macros eval sas
这是一个玩具示例,以帮助解决我遇到的更大问题.它主要涉及在引用更大的宏变量名时使用%eval()宏.
我创建了一个宏变量x_2,它使用循环的值'&it',变量被成功创建,如最终输出所示,但是我只能将它放到日志中而不评估&it + 1,使用大于1的循环时我需要做.
它似乎首先解决x_,发出警告,然后再评估x_2作为一个整体并给出输出.
我意识到这只是一个关于如何正确引用宏的问题,但我找不到任何使用评估作为宏变量名称的一部分的示例.
谢谢.
%macro testing;
%DO it = 1 %TO 1;
data dataset;
s=100;
t=99;
run;
data _null_;
set dataset;
if s = 100 then do;
call symput("x_%eval(&it+1)",t);
end;
run;
%put "&x_%eval(&it+1)";
%put &x_2;
%END;
%mend testing;
%testing;
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日志输出
MLOGIC(TESTING): %PUT "&x_%eval(&it+1)"
WARNING: Apparent symbolic reference X_ not resolved.
SYMBOLGEN: Macro variable IT resolves to 1
SYMBOLGEN: Macro variable X_2 resolves to 99
" 99"
MLOGIC(TESTING): %PUT &x_2
SYMBOLGEN: Macro variable X_2 resolves to 99
99
MLOGIC(TESTING): %DO loop index variable IT is now 2; loop will not iterate again.
MLOGIC(TESTING): Ending execution.
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实际上,SAS在调用%eval函数之前执行变量替换最简单的解决方案是在之前的语句中调用%eval
%let xNr = %eval(&it+1);
%put "&&x_&xNr";
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双&符号用于延迟评估x_&xNr
直到&xNr
评估到2
并且没有x_
未定义的警告.
SYMBOLGEN: Macro variable IT resolves to 1
SYMBOLGEN: && resolves to &.
SYMBOLGEN: Macro variable XNR resolves to 2
SYMBOLGEN: Macro variable X_2 resolves to 99
" 99"
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