如何从Oracle-Procedure中获得一个？

Question

我有这个程序:

CREATE OR REPLACE PROCEDURE CONV1(
    pDate   IN  VARCHAR2,
    pYear  OUT number,
    pMonth OUT number,
    pDay   OUT number
)
AS
    lDate   DATE;
BEGIN
    lDate := to_date(pDate, 'DD.MM.YYYY HH24:MI:SS');
    pYear := to_number(to_char(lDate, 'YYYY'));
    pMonth := to_number(to_char(lDate, 'MM'));
    pDay := to_number(to_char(lDate, 'DD'));

END CONV1;
/

如果我只想要其中一个出局,我该如何调用此程序？(喜欢Select FMAN_STAT_CONV1('16.07.2010', pDay) from dual;(这不是工作顺便说一句))

格尔茨!

Answer 1

创建将使用过程conv1的函数,但只返回一个值.

或者甚至更好地适合您的特定情况

SELECT to_char(to_date(your_date, 'DD.MM.YYYY HH24:MI:SS'), 'DD') from dual.

或者常见的情况是:

CREATE OR REPLACE FUNCTION CONV2(
  pDate   IN  VARCHAR2
) 
RETURN NUMBER
IS
  pDay   number;
  pMonth number;
  pYear  number;

BEGIN
   conv1(pDate, pYear, pMonth, pDay);
   return pDay;
END;