我想创建一个 json 文件,例如
{
"a":["12","34","23",...],
"b":["13","14","45",....],
.
.
.
}
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密钥应来自列表:
lis = ['a','b',...]
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以及来自 sql 查询“select id from”+ i 的值,我在其中通过“i”迭代列表。该查询仅返回列 ID。
这是示例代码:
lis = ['a','b','c']
len_obj = len(lis)
with open("Dataset.json", 'w') as file:
for i in lis:
file.write(i)
obj_query = i + '_query'
obj_query = sf.query("select id from " + i)
jsondata = json.loads(json.dumps(obj_query['records']))
length = len(jsondata)
i = {}
k = 0
for j in range(length):
obj_id = jsondata[j]['Id']
# print("id " + obj_id)
if k == 0:
ids = "\"" + obj_id + "\""
k = 1
else:
ids = ids + ",\"" + obj_id + "\""
if count != len_obj - 1:
file.write(ids)
else:
file.write(ids)
count += 1
file.write("}")
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最终输出应该是这样的:
{
"a":["12","23",...],
"b":["234","456",...],
}
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这是我的第一个博客,也是我的第一个程序。请引导我完成这个过程。
请原谅程序的缩进,因为我无法在这里正确地编写它。
您可以简单地创建一个包含您想要的值的字典,然后使用将其转换为 jsonjson.dumps
import json
data = {}
data['a'] = ["12","34","23"]
data['b'] = ["13","14","45"]
json_data = json.dumps(data)
print json_data
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您应该能够将整个事情浓缩为:
import json
tables = ["a", "b", "c", "d"]
data = {}
for t in tables:
results = sf.query("select id from %s" % t)["records"]
data[t] = [r["id"] for r in results]
with open("Dataset.json", "w") as f:
json.dump(data, f)
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