Haskell中的语法错误

Question

编译Haskell脚本时出错.请帮忙:

main = do
let bmiTell weight height
    | weight / height ^ 2 <= 18.5 = "You're underweight, you emo, you!"
    | weight / height ^ 2 <= 25.0 = "You're supposedly normal. Pffft, I bet you're ugly!"
    | weight / height ^ 2 <= 30.0 = "You're fat! Lose some weight, fatty!"
    | otherwise                   = "You're a whale, congratulations!"                = "You're a whale, congratulations!"

错误:(3,5)ghc:解析错误(可能是错误的缩进或括号不匹配)

Answer 1

两个问题

• 正如评论中所说,你的守卫至少需要缩进一个额外的空间(所以管道更加缩进了b)

• 您需要的不仅仅是块let内部do.例如,您可能想要测试您的功能!

解决了这些问题:

main = do
  let bmiTell weight height
       | weight / height ^ 2 <= 18.5 = "You're underweight, you emo, you!"
       | weight / height ^ 2 <= 25.0 = "You're supposedly normal. Pffft, I bet you're ugly!"
       | weight / height ^ 2 <= 30.0 = "You're fat! Lose some weight, fatty!"
       | otherwise                   = "You're a whale, congratulations!"  
  putStrLn $ bmiTell 6 1