java中双精度的选择排序

Question

我之前已经为int编写了选择排序方法,但是现在我正在处理一组双打.我已经尝试将变量更改为双精度,但我仍然得到"无法从double转换为int".任何帮助表示赞赏,谢谢!

//Original selection sort for ints
public static void selectionSort (int... arr)
{
    int i = 0, j = 0, smallest = 0;
    int temp = 0;

    for (i = 0;i<arr.length - 1;i++)
    {
        smallest = i;
        for (j = 1; j<arr.length - 1; j++)
        {
            if (arr[j]<arr[smallest])
                smallest = j;
        }
        temp = arr[smallest];
        arr[smallest] = arr[i];
        arr[i] = temp;

    }
}

//Attempted selection sort with doubles
public static void selectionSort (double...arr )
{
    double i = 0.0, j = 0.0, smallest = 0.0;
    double temp = 0.0;

    for (i = 0.0;i<arr.length - 1.0;i++)
    {
        smallest = i;
        for (j = 1.0; j<arr.length - 1.0; j++)
        {
            if (arr[j]<arr[smallest]) //error here with smallest and j
                smallest = j;
        }
        temp = arr[smallest]; //error here with smallest
        arr[smallest] = arr[i]; //error here with smallest and i
        arr[i] = temp; //error here with i

    }
}

Answer 1

问题是您还使用了double来索引数组.所以试试这个:

public static void selectionSort (double...arr)
{
    int i = 0, j = 0, smallest = 0;
    double temp = 0.0;

    for (i = 0; i < arr.length - 1; i++)
    {
        smallest = i;
        for (j = 1; j < arr.length - 1; j++)
        {
            if (arr[j] < arr[smallest])
                smallest = j;
        }
        temp = arr[smallest];
        arr[smallest] = arr[i];
        arr[i] = temp;
    }
}

正如您所看到的,仍然有双精度作为参数,temp-value和arr-array也仍然是双精度数,但用于数组的索引是整数.

索引总是int.例如,当我们有一个字符串数组时,我们仍然使用int作为索引:

String[] sArray = {
    "word1",
    "word2",
    "word3"
}
int index = 1;
String result = sArray[index]; // As you can see we use an int as index, and the result is a String
// In your case, the index is still an int, but the result is a double