Chr*_*ter 2 sql firebird coalesce
我遇到一些常用查询的性能问题.
SELECT
v.id,
coalesce((SELECT sum(amount) FROM artjournal WHERE variant_ref=v.id AND storage_ref=1 AND atype_ref in (1,3,4)), 0) "fv",
coalesce((SELECT sum(amount) FROM artjournal WHERE variant_ref=v.id AND storage_ref=1 AND atype_ref=2), 0) "ivo",
coalesce((SELECT sum(amount) FROM artjournal WHERE variant_ref=v.id AND storage_ref=1 AND atype_ref=5), 0) "iio",
coalesce((SELECT sum(amount * mvalue) FROM artjournal WHERE variant_ref=v.id AND storage_ref=1), 0) "vw"
FROM productvariant v
Run Code Online (Sandbox Code Playgroud)
因为artjournal是一张大桌子,每天都有成千上万的新唱片,演出变得越来越糟糕.
我有所有ID字段的索引.
有没有办法重写这个语句来加快速度?或者我可以使用不同的方式从artjournal表中检索数据,如果结果为null,则返回0?
谢谢你的想法,
克里斯蒂安
看起来你想要一个过滤的聚合:
SELECT v.id,
sum(case when a.atype_ref in (1,3,4) then a.amount else 0 end) as "fv",
sum(case when a.atype_ref = 2 then a.amount else 0 end) as "ivo",
sum(case when a.atype_ref = 5 then a.amount else 0 end) as "iio",
sum(a.amount * a.mvalue) as "vw"
FROM productvariant v
LEFT JOIN artjournal a ON a.variant_ref = v.id
WHERE storage_ref = 1
GROUP BY v.id;
Run Code Online (Sandbox Code Playgroud)
| 归档时间: |
|
| 查看次数: |
282 次 |
| 最近记录: |