说我已经匹配了一系列关系:
MATCH a-[r:BELONGS_TO]->b
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如何迭代每个关系并为其分配索引?在伪代码中:
for i in range(0, # of r's)
r.order = i
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这应该工作:
MATCH (a)-[r:BELONGS_TO]->(b)
WITH collect(r) as rels
WITH rels, range(0, size(rels)) AS is
UNWIND is AS i
WITH rels[i] as rel, i
SET rel.order = i
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你可以稍微破解一下:
MATCH (a)-[r:BELONGS_TO]->(b)
WITH collect(r) as relationships
UNWIND range(0, size(relationships)-1) as x
RETURN relationships[x]
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