use*_*827 21 python namedtuple
我有一个命名元组,我赋值如下:
class test(object):
self.CFTs = collections.namedtuple('CFTs', 'c4annual c4perren c3perren ntfixing')
self.CFTs.c4annual = numpy.zeros(shape=(self.yshape, self.xshape))
self.CFTs.c4perren = numpy.zeros(shape=(self.yshape, self.xshape))
self.CFTs.c3perren = numpy.zeros(shape=(self.yshape, self.xshape))
self.CFTs.ntfixing = numpy.zeros(shape=(self.yshape, self.xshape))
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有没有办法循环命名元组的元素?我试过这样做,但不起作用:
for fld in self.CFTs._fields:
self.CFTs.fld= numpy.zeros(shape=(self.yshape, self.xshape))
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Paw*_*ski 28
namedtuple是一个元组,所以你可以像普通元组一样迭代:
>>> from collections import namedtuple
>>> A = namedtuple('A', ['a', 'b'])
>>> for i in A(1,2):
print i
1
2
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但元组是不可变的,所以你不能改变它的价值
如果您需要可以使用的字段名称:
>>> a = A(1, 2)
>>> for name, value in a._asdict().iteritems():
print name
print value
a
1
b
2
>>> for fld in a._fields:
print fld
print getattr(a, fld)
a
1
b
2
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您可以像普通元组一样简单地循环这些项目:
MyNamedtuple = namedtuple("MyNamedtuple", "a b")
a_namedtuple = MyNamedtuple(a=1, b=2)
for i in a_namedtuple:
print(i)
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从Python 3.6开始,如果您需要属性名称,您现在需要执行以下操作:
for name, value in a_namedtuple._asdict().items():
print(name, value)
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如果你尝试使用a_namedtuple._asdict().iteritems()它会抛出 AttributeError: 'collections.OrderedDict' object has no attribute 'iteritems'
小智 6
from collections import namedtuple
point = namedtuple('Point', ['x', 'y'])(1,2)
for k, v in zip(point._fields, point):
print(k, v)
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输出:
x 1
y 2
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