触摸事件不返回触摸数据

VSO*_*VSO 12 javascript touch angularjs jqlite

编辑:"这不能在Angular UI Modals中完成"是一个有效的答案,如果实际情况如此.

这是我从触摸事件中获得的返回数据.显然缺少任何有用的触摸X/Y坐标(https://developer.mozilla.org/en-US/docs/Web/API/TouchEvent/changedTouches).这是一个毫无希望的通用问题,但是,任何想法?传递给触摸时执行的函数的"event"对象:

{
      "originalEvent": {
        "isTrusted": true
      },
      "type": "touchstart",
      "timeStamp": 1450388006795,
      "jQuery203026962137850932777": true,
      "which": 0,
      "view": "$WINDOW",
      "target": {},
      "shiftKey": false,
      "metaKey": false,
      "eventPhase": 3,
      "currentTarget": {},
      "ctrlKey": false,
      "cancelable": true,
      "bubbles": true,
      "altKey": false,
      "delegateTarget": {},
      "handleObj": {
        "type": "touchstart",
        "origType": "touchstart",
        "data": null,
        "guid": 2026,
        "namespace": ""
      },
      "data": null
    }
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现在,这是在画布中的角度UI模式,但鼠标事件工作正常.这是我的元素btw:

link: function(scope, element, attrs, model){
                //scope.canvasElem = element[0].children[0].children[0];
                scope.canvasElem = angular.element($('.touchScreen'))[0];
                scope.ctx = scope.canvasElem.getContext('2d');
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这是我如何绑定的一个例子:

element.bind('touchstart', scope.touchStart);
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编辑,这是一个用于比较的mousedown事件对象:

{
  "originalEvent": {
    "isTrusted": true
  },
  "type": "mousedown",
  "timeStamp": 1450389131400,
  "jQuery20309114612976554781": true,
  "toElement": {},
  "screenY": 436,
  "screenX": 726,
  "pageY": 375,
  "pageX": 726,
  "offsetY": 81,
  "offsetX": 41,
  "clientY": 375,
  "clientX": 726,
  "buttons": 1,
  "button": 0,
  "which": 1,
  "view": "$WINDOW",
  "target": {},
  "shiftKey": false,
  "relatedTarget": null,
  "metaKey": false,
  "eventPhase": 3,
  "currentTarget": {},
  "ctrlKey": false,
  "cancelable": true,
  "bubbles": true,
  "altKey": false,
  "delegateTarget": {},
  "handleObj": {
    "type": "mousedown",
    "origType": "mousedown",
    "data": null,
    "guid": 2025,
    "namespace": ""
  },
  "data": null
}
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Key*_*ria 0

要获取 x 和 y 坐标,请尝试使用以下代码

x1 = event.touches[0].pageX;
y1 = event.touches[0].pageY;
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