合并依赖于另一个的结果集的查询

Question

我运行此查询以根据评级,类别等内容从我的wordpress数据库中获取20个随机项

 SELECT (A.user_votes/A.user_voters) as site_rating, B.ID as post_id, B.post_author, B.post_date,E.name as category
            FROM `wp_gdsr_data_article` as A 
                INNER JOIN `wp_posts` as B ON (A.post_id = B.id) 
                INNER JOIN wp_term_relationships C ON (B.ID = C.object_id) 
                INNER JOIN wp_term_taxonomy D ON (C.term_taxonomy_id = D.term_taxonomy_id) 
                INNER JOIN wp_terms E ON (D.term_id = E.term_id) 
            WHERE 
                B.post_type = 'post' AND
                B.post_status = 'publish' AND
                D.taxonomy='category' AND
                E.name NOT IN ('Satire', 'Declined', 'Outfits','Unorganized', 'AP') 
            ORDER BY RAND()
            LIMIT 20

然后,对于随机项的每个结果,我想找到一个与随机项非常相似的对应项(大约相同的评级)但不相同,也是用户没有看到的项:

SELECT ABS($site_rating-(A.user_votes/A.user_voters)) as diff, (A.user_votes/A.user_voters) as site_rating, B.ID as post_id, B.post_author, B.post_date,E.name as category ,IFNULL(F.count,0) as count
            FROM `wp_gdsr_data_article` as A 
                INNER JOIN `wp_posts` as B ON (A.post_id = B.id) 
                INNER JOIN wp_term_relationships C ON (B.ID = C.object_id) 
                INNER JOIN wp_term_taxonomy D ON (C.term_taxonomy_id = D.term_taxonomy_id) 
                INNER JOIN wp_terms E ON (D.term_id = E.term_id) 
                LEFT JOIN (
                    SELECT *,COUNT(*) as count FROM `verus` WHERE ip = '{$_SERVER['REMOTE_ADDR']}'
                ) as F ON (A.post_id = F.post_id_winner OR A.post_id = F.post_id_loser)
            WHERE 
                E.name = '$category' AND
                B.ID <> '$post_id' AND
                B.post_type = 'post' AND
                B.post_status = 'publish' AND
                D.taxonomy='category' AND
                E.name NOT IN ('Satire', 'Declined', 'Outfits','Unorganized', 'AP') 
            ORDER BY count ASC, diff ASC
            LIMIT 1

以下php变量引用上一个查询的结果

    $post_id = $result['post_id'];
    $category = $result['category'];
    $site_rating = $result['site_rating'];

并$_SERVER['REMOTE_ADDR']指用户的IP.

有没有办法将第一个查询与需要调用的20个额外查询结合起来查找相应的项目,这样我只需要1或2个查询？

---

编辑:这是简化连接的视图

CREATE VIEW `versus_random` AS
SELECT (A.user_votes/A.user_voters) as site_rating, B.ID as post_id, B.post_author, B.post_date,E.name as category 
FROM `wp_gdsr_data_article` as A 
    INNER JOIN `wp_posts` as B ON (A.post_id = B.id) 
    INNER JOIN wp_term_relationships C ON (B.ID = C.object_id) 
    INNER JOIN wp_term_taxonomy D ON (C.term_taxonomy_id = D.term_taxonomy_id) 
    INNER JOIN wp_terms E ON (D.term_id = E.term_id)
WHERE 
    B.post_type = 'post' AND
    B.post_status = 'publish' AND
    D.taxonomy='category' AND
    E.name NOT IN ('Satire', 'Declined', 'Outfits','Unorganized', 'AP') 

我现在尝试以下观点:

 SELECT post_id, 
    (
            SELECT INNER_TABLE.post_id
            FROM `versus_random` as INNER_TABLE
            WHERE 
                INNER_TABLE.post_id <> OUTER_TABLE.post_id
            ORDER BY (SELECT COUNT(*) FROM `versus` WHERE ip = '54' AND (INNER_TABLE.post_id = post_id_winner OR INNER_TABLE.post_id = post_id_loser)) ASC
            LIMIT 1
        ) as innerquery

    FROM `versus_random` as OUTER_TABLE
    ORDER BY RAND()
    LIMIT 20

但是查询只是超时并冻结了我的mysql.

Answer 1

我认为它应该像这样工作，但我手头没有任何 Wordpress 来测试它。当获取相关帖子的第二个查询仅获取related_post_id. 整个查询本身变成一个子查询，给定别名“X”（尽管如果您想继续字母表，您可以自由使用“G”。）

在外部查询中，帖子和数据文章的表再次连接（RA 和 RP），以根据内部查询中的 related_post_id 查询相关帖子的相关字段。这两个表是左连接的（并且以相反的顺序），因此如果没有找到相关帖子，您仍然可以获得主帖子。

SELECT 
  X.site_rating,
  X.post_id,
  X.post_author,
  X.post_date,
  X.category,
  RA.user_votes / RA.user_voters as related_post_site_rating, 
  RP.ID as related_post_id, 
  RP.post_author as related_post_author, 
  RP.post_date as related_post_date,
  RP.name as related_category,
FROM       
  ( SELECT 
      (A.user_votes/A.user_voters) as site_rating, 
      B.ID as post_id, B.post_author, B.post_date,E.name as category,
      ( SELECT 
          RB.ID as post_id
        FROM `wp_gdsr_data_article` as RA 
            INNER JOIN `wp_posts` as RB ON (RA.post_id = RB.id) 
            INNER JOIN wp_term_relationships RC ON (RB.ID = RC.object_id) 
            INNER JOIN wp_term_taxonomy RD ON (RC.term_taxonomy_id = RD.term_taxonomy_id) 
            INNER JOIN wp_terms RE ON (RD.term_id = RE.term_id) 
            LEFT JOIN (
                SELECT *,COUNT(*) as count FROM `verus` WHERE ip = '{$_SERVER['REMOTE_ADDR']}'
            ) as RF ON (RA.post_id = RF.post_id_winner OR RA.post_id = RF.post_id_loser)
        WHERE 
            RE.name = E.name AND
            RB.ID <> B.ID AND
            RB.post_type = 'post' AND
            RB.post_status = 'publish' AND
            RD.taxonomy='category' AND
            RE.name NOT IN ('Satire', 'Declined', 'Outfits','Unorganized', 'AP') 
        ORDER BY count ASC, diff ASC
        LIMIT 1) as related_post_id

    FROM `wp_gdsr_data_article` as A 
        INNER JOIN `wp_posts` as B ON (A.post_id = B.id) 
        INNER JOIN wp_term_relationships C ON (B.ID = C.object_id) 
        INNER JOIN wp_term_taxonomy D ON (C.term_taxonomy_id = D.term_taxonomy_id) 
        INNER JOIN wp_terms E ON (D.term_id = E.term_id)
    WHERE 
        B.post_type = 'post' AND
        B.post_status = 'publish' AND
        D.taxonomy='category' AND
        E.name NOT IN ('Satire', 'Declined', 'Outfits','Unorganized', 'AP') 
    ORDER BY RAND()
    LIMIT 20
  ) X
  LEFT JOIN `wp_posts` as RP ON RP.id = X.related_post_id 
  LEFT JOIN `wp_gdsr_data_article` as RA.post_id = RP.id