Dej*_*jan 3 t-sql sql-server sql-server-2014
我想显示两列的减法.从第一列我需要得到所有值的总和并减去第二列中的每个值.
这是表结构:
id | name | col1 | col2 | date
------------------------------------
432| xxx | 0 | 15 |2015-11-17
432| yyy | 10 | 30 |2015-11-19
432| zzz | 60 | 40 |2015-11-20
433| aaa | 0 | 60 |2015-11-17
433| bbb | 80 | 20 |2015-11-19
433| ccc | 60 | 10 |2015-11-20
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公式应该去:
sum(col1) = 70 =>>> WHERE ID = 432
70 - col2 col3
-------------------------
=> 70 - 15 = 55
=> 70 - (30 + 15) = 25
=> 70 - (40 + 45) = -15
---------------------------
sum(col1) = 140 ===>> WHERE ID = 433
140 - col2 col3
-------------------------
=> 140 - 60 = 80
=> 140 - (60 + 20) = 60
=> 140 - (10 + 80) = 50
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结果是col3,输出应该像
id | name | col1 | col2 | col3 | date
-------------------------------------------
432| xxx | 0 | 15 | 55 | 2015-11-17
432| yyy | 10 | 30 | 25 | 2015-11-19
432| zzz | 60 | 40 | -15 | 2015-11-20
433| aaa | 0 | 60 | 80 | 2015-11-17
433| bbb | 80 | 20 | 60 | 2015-11-19
433| ccc | 60 | 10 | 50 | 2015-11-20
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编辑:如果我需要的值取决于组作为432和433 id列.
架构信息
DECLARE @TEST TABLE
(
id INT,
name VARCHAR(10),
col1 INT,
col2 int
)
INSERT INTO @TEST VALUES
(432,'xxx',0, 15 ),
(432,'yyy',10, 30 ),
(432,'zzz',60, 40 ),
(433,'aaa',0, 60 ),
(433,'bbb',80, 20 ),
(433,'ccc',60, 10 )
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询问
SELECT T.id ,
T.name ,
T.col1 ,
T.col2 ,
SUM(T.col1) OVER( PARTITION BY T.id ORDER BY T.id ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING)
- SUM(T.col2) OVER ( PARTITION BY T.id ORDER BY T.id ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW ) AS col3
FROM @TEST T;
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结果
id | name | col1 | col2 | col3 |
---------------------------------
432 | xxx | 0 | 15 | 55 |
432 | yyy | 10 | 30 | 25 |
432 | zzz | 60 | 40 | -15 |
433 | aaa | 0 | 60 | 80 |
433 | bbb | 80 | 20 | 60 |
433 | ccc | 60 | 10 | 50 |
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