嵌套包括在sequelize？

Question

如何执行嵌套包含？我的表产品与注释有一对多的关系,表注释与users表有多对一的关系.所以评论有user_id和product_id.我的代码是这样的

var models = require('../models');

models.products.findAll({
    include: [
        {model: models.comments}
    ]
  }).then(function (products) {
    next(products);
  }).catch(function (err) {
    next(err);
  });
});

我得到了评论,但我想有类似的东西

models.products.findAll({
    include: [
        {model: models.comments.include(models.comments.users)}
    ]
  }) 

没有编写自定义查询,这可能吗？

Answer 1

提供的解决方案对我不起作用，这是我使用的打字稿版本并猜测续集版本：

// sequelize-typescript
models.products.findAll({
  where,
  include: [{
    model: Comment,
    include: [User]
  }]
});

// without typescript (guessing here)
models.products.findAll({
  where,
  include: [{
    model: models.comments,
    include: [{
      model: models.users
    }]
  }]
});

Answer 2

models.products.findAll({
  include: [
    {model: models.comments, include: [models.comments.users] }
  ]
}) 

Answer 3

有一个非常简单又简洁的方法！https://sequelize.org/docs/v6/advanced-association-concepts/eager-loading/#include-everything

// Fetch all models associated with User
User.findAll({ include: { all: true }});

// Fetch all models associated with User and their nested associations (recursively) 
User.findAll({ include: { all: true, nested: true }});