每n秒运行一定的代码

Question

有没有办法,例如,Hello World!每n秒打印一次？例如,程序将通过我拥有的任何代码,然后一旦它有5秒(有time.sleep())它将执行该代码.我会使用它来更新文件,而不是打印Hello World.

例如:

startrepeat("print('Hello World')", .01) # Repeats print('Hello World') ever .01 seconds

for i in range(5):
    print(i)

>> Hello World!
>> 0
>> 1
>> 2
>> Hello World!
>> 3
>> Hello World!
>> 4

Answer 1

import threading

def printit():
  threading.Timer(5.0, printit).start()
  print "Hello, World!"

printit()

# continue with the rest of your code

Answer 2

我对这个主题的谦虚态度,对Alex Martelli的回答的概括,以及start()和stop()控制:

from threading import Timer

class RepeatedTimer(object):
    def __init__(self, interval, function, *args, **kwargs):
        self._timer     = None
        self.interval   = interval
        self.function   = function
        self.args       = args
        self.kwargs     = kwargs
        self.is_running = False
        self.start()

    def _run(self):
        self.is_running = False
        self.start()
        self.function(*self.args, **self.kwargs)

    def start(self):
        if not self.is_running:
            self._timer = Timer(self.interval, self._run)
            self._timer.start()
            self.is_running = True

    def stop(self):
        self._timer.cancel()
        self.is_running = False

用法:

from time import sleep

def hello(name):
    print "Hello %s!" % name

print "starting..."
rt = RepeatedTimer(1, hello, "World") # it auto-starts, no need of rt.start()
try:
    sleep(5) # your long-running job goes here...
finally:
    rt.stop() # better in a try/finally block to make sure the program ends!

特征:

• 仅限标准库,无外部依赖项
• start()stop()即使定时器已经启动/停止,也可以安全地多次呼叫
• 要调用的函数可以有位置和命名参数
• 您可以interval随时更改,它将在下次运行后生效.同样的args,kwargs甚至是function!

Answer 3

保存自己的精神分裂症情节并使用Advanced Python调度程序:http: //pythonhosted.org/APScheduler

代码很简单:

from apscheduler.scheduler import Scheduler

sched = Scheduler()
sched.start()

def some_job():
    print "Every 10 seconds"

sched.add_interval_job(some_job, seconds = 10)

....
sched.shutdown()

Answer 4

def update():
    import time
    while True:
        print 'Hello World!'
        time.sleep(5)

那将作为一个功能运行.将while True:使它永远运行下去.如果需要,您可以随时将其从功能中取出.

Answer 5

这是一个与APScheduler 3.00+兼容的简单示例:

# note that there are many other schedulers available
from apscheduler.schedulers.background import BackgroundScheduler

sched = BackgroundScheduler()

def some_job():
    print('Every 10 seconds')

# seconds can be replaced with minutes, hours, or days
sched.add_job(some_job, 'interval', seconds=10)
sched.start()

...

sched.shutdown()

或者,您可以使用以下内容.与许多替代方案不同,此计时器将每n秒精确执行所需的代码(无论代码执行的时间如何).因此,如果您无法承受任何漂移,这是一个很好的选择.

import time
from threading import Event, Thread

class RepeatedTimer:

    """Repeat `function` every `interval` seconds."""

    def __init__(self, interval, function, *args, **kwargs):
        self.interval = interval
        self.function = function
        self.args = args
        self.kwargs = kwargs
        self.start = time.time()
        self.event = Event()
        self.thread = Thread(target=self._target)
        self.thread.start()

    def _target(self):
        while not self.event.wait(self._time):
            self.function(*self.args, **self.kwargs)

    @property
    def _time(self):
        return self.interval - ((time.time() - self.start) % self.interval)

    def stop(self):
        self.event.set()
        self.thread.join()


# start timer
timer = RepeatedTimer(10, print, 'Hello world')

# stop timer
timer.stop()

Answer 6

这是一个每秒都不创建新线程的版本n:

from threading import Event, Thread

def call_repeatedly(interval, func, *args):
    stopped = Event()
    def loop():
        while not stopped.wait(interval): # the first call is in `interval` secs
            func(*args)
    Thread(target=loop).start()    
    return stopped.set

该事件用于停止重复:

cancel_future_calls = call_repeatedly(5, print, "Hello, World")
# do something else here...
cancel_future_calls() # stop future calls

请参阅改进setInterval python的当前实现