如何让C#Xamarin.Android应用程序在手机启动时运行？

Question

我一直试图让手机启动时运行一个应用程序,并在我按下时最终运行应用程序KeyCode.CameraButton.我正在使用一个名为BootReceiver,继承自的类BroadcastReceiver.这是我的班级:

    namespace ColorPoint.Xamarin.XAndroid
    {
        [BroadcastReceiver]
        [IntentFilter(new[] { Intent.ActionBootCompleted }, Priority = (int)IntentFilterPriority.LowPriority)]
        public class BootReceiver : BroadcastReceiver
        { 
            public override void OnReceive(Context context, Intent intent)
            {
                Intent serviceStart = new Intent(context, typeof(MainActivity));
                context.StartActivity(serviceStart);                
            }
       }
}

当广播收到时,应用程序重新启动.我从adb命令提示符运行它来模拟启动和手机重启!

adb -s device-or-emulator-id shell am broadcast -a android.intent.action.BOOT_COMPLETED

这是我的清单文件,不确定它是否正确!

    '<?xml version="1.0" encoding="utf-8"?>
<manifest xmlns:android="http://schemas.android.com/apk/res/android" package="ColorPoint.Xamarin.XAndroid" android:installLocation="auto" android:versionCode="1" android:versionName="1.0">
    <uses-sdk android:minSdkVersion="19" android:targetSdkVersion="19" />
    <application android:label="Rexson Barcode Scanner" android:icon="@drawable/icon">
    <receiver android:name=".BootReceiver">
      <intent-filter>
        <action android:name="android.intent.action.BOOT_COMPLETED" />
      </intent-filter>
    </receiver>
  </application>
    <uses-permission android:name="android.permission.INTERNET" />
    <uses-permission android:name="android.permission.CAMERA" />
    <uses-permission android:name="android.permission.ACCESS_COARSE_LOCATION" />
    <uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
    <uses-permission android:name="android.permission.ACCESS_WIFI_STATE" />
    <uses-permission android:name="android.permission.READ_INPUT_STATE" />
    <uses-permission android:name="android.permission.RECEIVE_BOOT_COMPLETED" />
    <uses-feature android:name="android.hardware.camera" />
    <uses-feature android:name="android.hardware.camera.autofocus" />
    <activity android:name="MainActivity" />
    <activity android:name="com.google.zxing.client.android.CaptureActivity" android:exported="false" android:windowSoftInputMode="stateAlwaysHidden">
        <intent-filter>
            <action android:name="com.phonegap.plugins.barcodescanner.SCAN" />
            <category android:name="android.intent.category.DEFAULT" />
        </intent-filter>
    </activity>
</manifest>'

需要一步一步地完成这一步但不能很好地调试它,当我模拟启动时,电话重置是多么的错误!

我刚尝试手动重启,应用程序试图启动,但说"不幸的是[myapp]已停止工作"然后再次手机重启

似乎它试图打开但崩溃immediatley,然后重新启动手机

从另一个例子发现这个但同样的事情,只需重新启动手机..

public override void OnReceive(Context context, Intent intent)
        {
            if (intent.Action == Intent.ActionBootCompleted)
            {
                bool autoRestart = false;
                var sp = context.GetSharedPreferences("preferences", FileCreationMode.Private);
                autoRestart = sp.GetBoolean("autoRestart", false);
                if (autoRestart)
                {
                    Intent serviceStart = new Intent(context, typeof(MainActivity));
                    serviceStart.AddFlags(ActivityFlags.NewTask);
                    context.StartActivity(serviceStart);
                }
            }
           }

Answer 1

您需要将ActivityFlags.NewTask标志添加到intent中,因为您要在活动上下文之外启动活动.

崩溃是因为a Android.Util.AndroidRuntimeException是由启动接收器生成的.

解决方案:

[BroadcastReceiver]
[IntentFilter(new[] { Intent.ActionBootCompleted }, Priority = (int)IntentFilterPriority.LowPriority)]
public class BootReceiver : BroadcastReceiver
{ 
    public override void OnReceive(Context context, Intent intent)
    {
        Intent serviceStart = new Intent(context, typeof(MainActivity));
        serviceStart.AddFlags (ActivityFlags.NewTask);
        context.StartActivity(serviceStart);                
    }
}