PHP RabbitMQ setTimeout或其他选项停止等待队列

Question

我需要创建一个简单的队列管理器来将数字从发件人传递给消费者.RabbitMQ提供的Hello World教程几乎覆盖了70%.

但我需要将队列更改为永远不会等待传入的消息.或者在一定数量的消息后停止等待.我阅读并尝试了其他帖子中的一些解决方案,但它不起作用.

rabbitmq AMQP :: consume() - 未定义的方法.还有另一种方法,wait_frame但它受到保护.

和其他帖子是python,我不明白.

<?php

require_once __DIR__ . '/vendor/autoload.php';
require 'config.php';
use PhpAmqpLib\Connection\AMQPStreamConnection;

function recieveQueue($queueName){
    $connection = new AMQPStreamConnection('localhost', 5672, 'guest', 'guest');

    // try{
    //  $connection->wait_frame(10);
    // }catch(AMQPConnectionException $e){
    //  echo "asdasd";
    // }

    $channel = $connection->channel();

    $channel->queue_declare($queueName, false, false, false, false);

    echo ' [*] Waiting for messages. To exit press CTRL+C', "\n";

    $callback = function($msg) {
        echo " [x] Received ", $msg->body, "\n";

    };

    // $tag = uniqid() . microtime(true);
    // $queue->consume($callback, $flags, $tag);

    $channel->basic_consume($queueName, '', false, true, false, false, $callback);

    // $channel->cancel($tag);

    while(count($channel->callbacks)) {
        $channel->wait();
    }

    echo "\nfinish";
}

recieveQueue('vtiger');

?>

Answer 1

修改while循环中的wait():

$timeout = 55;
while(count($channel->callbacks)) {
    $channel->wait(null, false, $timeout);
}

Answer 2

wait函数只适用于套接字,我们必须捕获异常:

 $timeout = 5;
    while (count($channel->callbacks)) {
        try{
            $channel->wait(null, false , $timeout);
        }catch(\PhpAmqpLib\Exception\AMQPTimeoutException $e){
            $channel->close();
            $connection->close();
            exit;
        }
    }