Haskell无法从GADT构造函数中找出类型

Question

在长长的例子中提前道歉,我无法想出一个较短的例子.

让我们定义一个类型类Box,除了包含另一种类型之外什么都不做Content.

{-# LANGUAGE GADTs                     #-}
{-# LANGUAGE TypeFamilies              #-}

class Box t where
    type Content t

data IntBox = IntBox
data StringBox = StringBox

我们来写一些例子:

instance Box IntBox where
    type Content IntBox = Int

instance Box StringBox where
    type Content StringBox = String

data JointBox a b = JointBox a b

instance (Box a, Box b) => Box (JointBox a b) where
    type Content (JointBox a b) = Either (Content a) (Content b)

到目前为止,这些都是编译和工作.输入GADT.我想要一个由一个盒子及其内容构成的代数数据类型.构造函数完全决定了框的类型.

data ABox t where
    AnIntBox :: IntBox -> ABox IntBox
    AStringBox :: StringBox -> ABox StringBox
    AnIntOrStringBox :: JointBox IntBox StringBox -> ABox (JointBox IntBox StringBox)

现在,在我看来,这意味着通过构造函数的模式匹配,ABox应该确定框的类型及其内容.但似乎并非如此:

frobABox :: (Content t) ->  ABox t              -> IO ()
frobABox     int           (AnIntBox _)         =  print $ int + 3
frobABox     string        (AStringBox _)       =  putStrLn $ reverse string
frobABox    (Left int)     (AnIntOrStringBox _) =  print $ int + 6
frobABox    (Right string) (AnIntOrStringBox _) =  putStrLn $ reverse string

这引发了很多错误,其中这两个错误对我来说最重要:

GADTAndTypeClassBug.hs:29:14:
    Couldn't match expected type ‘Content t’
                with actual type ‘Either t0 t1’
    The type variables ‘t0’, ‘t1’ are ambiguous
    Relevant bindings include
      frobABox :: Content t -> ABox t -> IO ()
        (bound at GADTAndTypeClassBug.hs:27:1)
    In the pattern: Left int
    In an equation for ‘frobABox’:
        frobABox (Left int) (AnIntOrStringBox _) = print $ int + 6

GADTAndTypeClassBug.hs:30:14:
    Couldn't match expected type ‘Content t’
                with actual type ‘Either t2 t3’
    The type variables ‘t2’, ‘t3’ are ambiguous
    Relevant bindings include
      frobABox :: Content t -> ABox t -> IO ()
        (bound at GADTAndTypeClassBug.hs:27:1)
    In the pattern: Right string
    In an equation for ‘frobABox’:
        frobABox (Right string) (AnIntOrStringBox _)
          = putStrLn $ reverse string

GADTAndTypeClassBug.hs:30:71:
    Couldn't match expected type ‘[Char]’ with actual type ‘t3’
      ‘t3’ is untouchable
        inside the constraints (t ~ JointBox IntBox StringBox)
        bound by a pattern with constructor
                   AnIntOrStringBox :: JointBox IntBox StringBox
                                       -> ABox (JointBox IntBox StringBox),
                 in an equation for ‘frobABox’
        at GADTAndTypeClassBug.hs:30:29-46
    Relevant bindings include
      string :: t3 (bound at GADTAndTypeClassBug.hs:30:20)
    In the first argument of ‘reverse’, namely ‘string’
    In the second argument of ‘($)’, namely ‘reverse string’

没有类型系列的更简单示例:

data UnitOrEither t where
    AUnit :: () -> UnitOrEither ()
    AnEither :: Either String Int -> UnitOrEither (Either String Int)

frob :: UnitOrEither t -> IO ()
frob   (AUnit _)       =  print ()
frob   (AnEither _)    =  print "Either"

所以有什么问题？

Answer 1

GADT模式匹配的细化从左到右进行.因此,对第二个参数匹配产生的类型细化frobABox将不适用于第一个参数.

您可以通过翻转以下参数来编译代码frobABox:

frobABox' :: ABox t              -> Content t -> IO ()
frobABox' (AnIntBox _)          int           =  print $ int + 3
frobABox' (AStringBox _)        string        =  putStrLn $ reverse string
frobABox' (AnIntOrStringBox _) (Left int)     =  print $ int + 6
frobABox' (AnIntOrStringBox _) (Right string) =  putStrLn $ reverse string

frobABox :: (Content t) ->  ABox t              -> IO ()
frobABox = flip frobABox'