PHP:从父方法中的静态方法调用子构造函数

mar*_*nve 10 php static constructor subclass

我希望在父类中有一个静态方法,它创建我调用此方法的子类的实例.

举个例子来说明这一点:

class parent {
    public static method make_objects($conditions){
        for (...){
            // here i want to create an instance
            // of whatever subclass i am calling make_objects on
            // based on certain $conditions
        }
    }
}

class sub extends parent{
    ...
}

$objects = sub::make_objects($some_conditions);

Vol*_*erK 11

从php 5.3开始,您可以使用static关键字

<?php
class A {
  public static function newInstance() {
    $rv = new static();  
    return $rv;
  }
}
class B extends A { }
class C extends B { }

$o = A::newInstance(); var_dump($o);
$o = B::newInstance(); var_dump($o);
$o = C::newInstance(); var_dump($o);
Run Code Online (Sandbox Code Playgroud)

版画

object(A)#1 (0) {
}
object(B)#2 (0) {
}
object(C)#1 (0) {
}
Run Code Online (Sandbox Code Playgroud)

编辑:另一个(类似的)例子

<?php
class A {
  public static function newInstance() {
    $rv = new static();  
    return $rv;
  }

  public function __construct() { echo " A::__construct\n"; }
}
class B extends A {
  public function __construct() { echo " B::__construct\n"; }
}
class C extends B {
  public function __construct() { echo " C::__construct\n"; }   
}

$types = array('A', 'B', 'C');
foreach( $types as $t ) {
  echo 't=', $t, "\n";
  $o = $t::newInstance();
  echo '  type of o=', get_class($o), "\n";
}
Run Code Online (Sandbox Code Playgroud)

版画

t=A
 A::__construct
  type of o=A
t=B
 B::__construct
  type of o=B
t=C
 C::__construct
  type of o=C
Run Code Online (Sandbox Code Playgroud)