vla*_*lka 11 android android-gridlayout
GridLayout当其中一个孩子Visibility被设置为时GONE,我想做一个,它被下一个孩子取代.

这不是我自己画的更好的解释.
我可以按照列数和宽度以及所有方式使布局工作.只是默认GONE行为GridLayout使得孩子只是消失而不是被替换,好像它不在那里,就像其他布局一样.
我确实尝试了很多东西,我尝试搜索SO和谷歌,但我似乎无法解决这个问题.这对于我正在处理的应用程序来说是最方便的布局.无论如何都要在布局中执行此操作而不必以编程方式执行此操作?或者两者的组合?
小智 6
如果您不需要再次将视图变为可见,您可以解决它从 GridLayout 中删除视图。
private void hideView(View view) {
GridLayout gridLayout = (GridLayout) view.getParent();
for (int i = 0; i < gridLayout.getChildCount(); i++) {
if (view == gridLayout.getChildAt(i)) {
gridLayout.removeViewAt(i);
break;
}
}
}
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解决方案是将RecyclerView与GridLayoutManager一起使用。关键是通过使用notifyItemRemoved通知适配器有关已删除项目的更改。在RecyclerViews中有许多自定义空间,例如用于消失项目的漂亮动画,屏幕上剩余项目的重新排列,项目装饰等。您可以根据自己的特定需要应用所有这些自定义和围绕删除项目的附加逻辑问题。
活动
public class MainActivity extends AppCompatActivity {
RecyclerView recyclerView;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
List<String> dataSet = getSampleDataSet();
recyclerView = (RecyclerView) findViewById(R.id.grid);
recyclerView.setAdapter(new MyAdapter(dataSet));
recyclerView.setLayoutManager(new GridLayoutManager(getApplicationContext(), 2));
}
private List<String> getSampleDataSet() {
List strings = new ArrayList();
strings.add("one");
strings.add("two");
strings.add("three");
strings.add("four");
strings.add("five");
strings.add("six");
return strings;
}
}
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适配器
public class MyAdapter extends RecyclerView.Adapter<MyViewHolder> {
List<String> dataSet;
public MyAdapter(List<String> dataSet) {
this.dataSet = dataSet;
}
@Override
public MyViewHolder onCreateViewHolder(ViewGroup parent, int viewType) {
TextView tileView = (TextView) LayoutInflater.from(parent.getContext()).inflate(R.layout.grid_item, parent, false);
MyViewHolder myViewHolder = new MyViewHolder(tileView);
return myViewHolder;
}
@Override
public void onBindViewHolder(MyViewHolder holder, final int position) {
holder.view.setText(dataSet.get(position));
holder.view.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View view) {
dataSet.remove(position);
notifyItemRemoved(position); // this notifies the adapter about item being removed
}
});
}
@Override
public int getItemCount() {
return dataSet.size();
}
}
class MyViewHolder extends RecyclerView.ViewHolder {
TextView view;
public MyViewHolder(TextView itemView) {
super(itemView);
view = itemView;
}
}
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活动布局
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent">
<android.support.v7.widget.RecyclerView
android:id="@+id/grid"
android:layout_width="match_parent"
android:layout_height="match_parent"/>
</RelativeLayout>
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网格项
<?xml version="1.0" encoding="utf-8"?>
<TextView
xmlns:android="http://schemas.android.com/apk/res/android"
android:id="@+id/gridItem"
android:layout_width="match_parent"
android:layout_height="50dp"
android:background="@color/colorPrimary"
android:textColor="@android:color/white"
android:gravity="center"
android:text="Tile"/>
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单击4.之后,在实际设备上,您将可以看到此操作的漂亮框架动画。
小智 5
解决同样的问题:
package ua.vsgroup.widgets;
import android.content.Context;
import android.support.v7.widget.GridLayout;
import android.util.AttributeSet;
import android.view.View;
public class vsGridLayout extends GridLayout {
View[] mChild = null;
public vsGridLayout(Context context, AttributeSet attrs, int defStyle) {
super(context, attrs, defStyle);
}
public vsGridLayout(Context context, AttributeSet attrs) {
this(context, attrs, 0);
}
public vsGridLayout(Context context) {
this(context, null);
}
private void arrangeElements() {
mChild = new View[getChildCount()];
for (int i = 0; i < getChildCount(); i++) {
mChild[i] = getChildAt(i);
}
removeAllViews();
for (int i = 0; i < mChild.length; i++) {
if (mChild[i].getVisibility() != GONE)
addView(mChild[i]);
}
for (int i = 0; i < mChild.length; i++) {
if (mChild[i].getVisibility() == GONE)
addView(mChild[i]);
}
}
@Override
protected void onLayout(boolean changed, int left, int top, int right, int bottom) {
arrangeElements();
super.onLayout(changed, left, top, right, bottom);
}
}
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