Ell*_*one 10 html css html-table button
我有以下代码:
<td>
<button class="btn btn-primary btn-xs" ng-click="r.changeView('requests/edit/' + request.id)">
<i class="fa fa-pencil-square-o"></i>
</button>
<button class="btn btn-primary btn-xs" ng-click="r.changeView('requests/edit/' + request.id)">
<i class="fa fa-step-backward"></i>
<i class="fa fa-step-forward"></i>
</button>
</td>
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它们出现在两条不同的线上.
如何让它们在同一条线上彼此相邻?
我尝试了一些事情float
,并display
但没有成功.
Ken*_*ney 19
如果我在代码段中添加该代码,则按钮彼此相邻,因此很难重现:
<table>
<tr>
<td>
<button class="btn btn-primary btn-xs" ng-click="r.changeView('requests/edit/' + request.id)">
<i class="fa fa-pencil-square-o"></i>Button1
</button>
<button class="btn btn-primary btn-xs" ng-click="r.changeView('requests/edit/' + request.id)">
<i class="fa fa-step-backward"></i>
<i class="fa fa-step-forward"></i>Button2
</button>
</td>
</tr>
</table>
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按钮已显示为inline-block
.也许桌子不够宽; 如果是这样,你可以试试<td style='white-space: nowrap'>
.