假设我有一个订阅表:
uid | subscription_type
------------------------
Alex | type1
Alex | type2
Alex | type3
Alex | type4
Ben | type2
Ben | type3
Ben | type4
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并且只想选择具有2个以上订阅但从未订阅类型1的用户
预期的结果是仅选择"Ben".
我很容易找到超过2个订阅的用户使用:
SELECT uid
FROM subscribes
GROUP BY uid
HAVING COUNT(*) > 2
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但是如何检查组中是否存在某些值?
谢谢您的帮助!
kro*_*lko 19
试试这个查询:
SELECT uid
FROM subscribes
GROUP BY uid
HAVING COUNT(*) > 2
AND max( CASE "subscription_type" WHEN 'type1' THEN 1 ELSE 0 END ) = 0
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创建示例表:
CREATE TABLE subscribes
(
uid NVARCHAR(MAX),
subscription_type NVARCHAR(MAX)
)
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插入值:
INSERT INTO subscribes
VALUES ('Alex', 'type1'), ('Alex', 'type2'), ('Alex', 'type3'), ('Alex', 'type4'), ('Ben', 'type2'), ('Ben', 'type3'), ('Ben', 'type4')
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SQL查询:
SELECT uid
FROM subscribes
GROUP BY uid
HAVING COUNT(*) > 2
AND MAX(CASE subscription_type WHEN 'type1' THEN 1 ELSE 0 END) = 0
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输出:
======
|uid |
------
|Ben |
======
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要检查某些东西是否不存在,请使用NOT EXISTS(...)
:
SELECT uid
FROM subscribes su
WHERE NOT EXISTS (SELECT *
FROM subscribes nx
WHERE nx.uid = su.uid AND nx.subscription_type = 'type1'
)
GROUP BY uid HAVING COUNT(*) > 2
;
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