sas*_*nin 7 haskell types monad-transformers
是否可以使用类型同义词作为monad变换器类型构造函数的参数?特别是,如果应用的monad变换器有一元类型的同义词,它是否可以用作另一个monad变换器中底层monad的类型?
从我看到的类型同义词不被接受为第一类类型构造函数,请参阅下面的示例和错误消息:
-- Using type synonym of a monad transformer in another monad transformer.
import Control.Monad.Reader
-- inner transformer
type A a = ReaderT Int IO a
-- type B a = ReaderT String A a
{- Error:
readert2.hs:8:0:
Type synonym `A' should have 1 argument, but has been given 0
In the type synonym declaration for `B'
-}
-- type B a = ReaderT String (A a) a
{- Error:
readert2.hs:15:27:
Kind mis-match
The second argument of `ReaderT' should have kind `* -> *',
but `A a' has kind `*'
In the type `ReaderT String (A a) a'
In the type synonym declaration for `B'
-}
type B a = ReaderT String (ReaderT Int IO) a
{- OK -}
main = do
r <- flip runReaderT 39 $ do
n <- ask :: A Int
s <- flip runReaderT "foo" $ (ask :: B String)
return $ n + length s
print r
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有没有办法避免A在定义中扩展类型同义词B a?
sdc*_*vvc 12
无法部分应用类型同义词.在这种特定情况下,您可以写
type A = ReaderT Int IO
type B a = ReaderT String A a
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[甚至更好type B = ReaderT String A地用于B另一个monad变换器]
通常,如果不使用newtype/data,转换是不可能的,例如:
type A a = Reader a Int
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不能等同地写成type A = ....在某种意义上,此功能将等同于类型级lambda \a -> Reader a Int.