没有xsd.exe的XML序列化和架构

Question

我使用XML序列化来读取我的Config-POCO.

要在Visual Studio中获取XML文件的智能感知支持,我需要一个模式文件.我可以使用xsd.exe mylibrary.dll创建架构,这很好用.

但是,如果我将对象序列化到文件系统,我希望始终创建模式.没有使用xsd.exe有什么办法吗？

Answer 1

谢谢,这对我来说是正确的方式.解:

XmlReflectionImporter importer = new XmlReflectionImporter();
XmlSchemas schemas = new XmlSchemas();
XmlSchemaExporter exporter = new XmlSchemaExporter(schemas);
Type type = toSerialize.GetType();
XmlTypeMapping map = importer.ImportTypeMapping(type);
exporter.ExportTypeMapping(map);

TextWriter tw = new StreamWriter(fileName + ".xsd");
schemas[0].Write(tw);
tw.Close();

Answer 2

Will上面发布的解决方案效果很好,除了我意识到生成的模式没有反映不同类成员的属性.例如,使用序列化提示属性修饰的类(请参阅下面的示例)将无法正确呈现.

    public class Test
    {
        [XmlAttribute()]
        public string Attribute { get; set; }
        public string Description { get; set; }

        [XmlArray(ElementName = "Customers")]
        [XmlArrayItem(ElementName = "Customer")]
        public List<CustomerClass> blah { get; set; }

    }

为了解决这个问题,我创建了一些帮助函数,它们使用反射来遍历类层次结构,读取属性,并填充可以传递给XmlReflectionImporter的XmlAttributeOverrides对象.

    public static void AttachXmlAttributes(XmlAttributeOverrides xao, Type t)
    {
        List<Type> types = new List<Type>();
        AttachXmlAttributes(xao, types, t);
    }

    public static void AttachXmlAttributes(XmlAttributeOverrides xao, List<Type> all, Type t)
    {
        if(all.Contains(t))
            return;
        else
            all.Add(t);

        XmlAttributes list1 = GetAttributeList(t.GetCustomAttributes(false));
        xao.Add(t, list1);

        foreach (var prop in t.GetProperties())
        {
            XmlAttributes list2 = GetAttributeList(prop.GetCustomAttributes(false));
            xao.Add(t, prop.Name, list2);
            AttachXmlAttributes(xao, all, prop.PropertyType);
        }
    }

    private static XmlAttributes GetAttributeList(object[] attributes)
    {
        XmlAttributes list = new XmlAttributes();
        foreach (var attribute in attributes)
        {
            Type type = attribute.GetType();
            if (type.Name == "XmlAttributeAttribute") list.XmlAttribute = (XmlAttributeAttribute)attribute;
            else if (type.Name == "XmlArrayAttribute") list.XmlArray = (XmlArrayAttribute)attribute;
            else if (type.Name == "XmlArrayItemAttribute") list.XmlArrayItems.Add((XmlArrayItemAttribute)attribute);

        }
        return list;
    }
    public static string GetSchema<T>()
    {
        XmlAttributeOverrides xao = new XmlAttributeOverrides();
        AttachXmlAttributes(xao, typeof(T));

        XmlReflectionImporter importer = new XmlReflectionImporter(xao);
        XmlSchemas schemas = new XmlSchemas();
        XmlSchemaExporter exporter = new XmlSchemaExporter(schemas);
        XmlTypeMapping map = importer.ImportTypeMapping(typeof(T));
        exporter.ExportTypeMapping(map);

        using (MemoryStream ms = new MemoryStream())
        {
            schemas[0].Write(ms);
            ms.Position = 0;
            return new StreamReader(ms).ReadToEnd();
        }
    }

希望这有助于其他人.

Answer 3

看看System.Xml.Serialization.XmlSchemaExporter班级。我不记得确切的细节，但该命名空间中有足够的功能来完成您的要求。