Dea*_*Iss 1 groovy group-by aggregate sum
我想知道汇总数据的最佳方法是在Groovy中吗?
可以说我有以下数据:
[
[id: 1, name: bob, age:20, numberOfPackages: 10, numberOfPurchases:20 ],
[id: 1, name: bob, age:20, numberOfPackages: 5, numberOfPurchases:6 ],
[id: 2, name: Rob, age:22, numberOfPackages: 3, numberOfPurchases:5 ],
]
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我想将它转化为以下(合并ID / 姓名 / 年龄,但和价格 / 数量每购买ID):
[
[id: 1, name: bob, age:20, numberOfPackages: 15, numberOfPurchases:26 ],
[id: 2, name: Rob, age:22, numberOfPackages: 3, numberOfPurchases:5 ],
]
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汇总价格和分别购买的数量没有什么意义,您的意思是:
def data = [
[id: 1, name: 'bob', age:20, price: 10, numberOfPurchases:20],
[id: 1, name: 'bob', age:20, price: 5, numberOfPurchases:6],
[id: 2, name: 'rob', age:22, price: 3, numberOfPurchases:5]
]
data.groupBy { [id:it.id, name:it.name, age:it.age] }.collect { k, v ->
[id:k.id,
name:k.name,
age:k.age,
spend:v.collect { it.price * it.numberOfPurchases }.sum()]
}
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这使:
[
[id:1, name:'bob', age:20, spend:230],
[id:2, name:'rob', age:22, spend:15]
]
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