输入2个整数并得到二进制,brgc和汉明距离

Question

除了海明距离外,我得到了一切.我一直得到错误"int()无法使用显式基础转换非字符串"

这是我的代码:

def int2bin(n):                                
    if n:
        bits = []
        while n:
            n,remainder = divmod(n, 2)
            bits.insert(0, remainder)
        return bits
    else: return [0]

def bin2gray(bits):                  
    return bits[:1] + [i ^ ishift for i, ishift in zip(bits[:-1], bits[1:])]

def hamming(a,b):                        
    assert len(a) == len(b)
    count,z = 0,int(a,2)^int(b,2)
    while z:
        count += 1
        z &= z-1 
    return count

def main():
    a = int(input("Positive integer 1: "))        
    b = int(input("Positive integer 2: "))
    print('int:%2i    binary:%12r    BRGC:%12r' %    
          ( a,
            int2bin(a),
        bin2gray(int2bin(a))
           ))
    print('int:%2i    binary:%12r    BRGC:%12r' %
          ( b,
            int2bin(b),
        bin2gray(int2bin(b))
           ))
    print('hamming|%2     %12r        &12r' %
          (hamming(int2bin(a),int2bin(b)),
           hamming(bin2gray(int2bin(a)),bin2gray(int2bin(b)))
           ))

main()

输出应该是这样的

int: 5 binary: [1, 0, 1] brgc: [1, 1, 1]    
int: 6 binary: [1, 1, 0] brgc: [1, 0, 1]    
hamming            2               1

请帮忙!

Answer 1

尝试这个实现(a并b期望是整数):

def hamming(a, b):
    return bin(a^b).count('1')

在这里我xor a和b得到二进制,其中代表a和之间的差异b.比我算数.