chi*_*der 7 python dictionary nested
我有一个很长的字典列表,其中包含字符串索引和整数值.字典中的许多键都是相同的,但不是全部.我想生成一个字典,其中键是单独字典中键的并集,值是每个字典中与该键对应的所有值的总和.(例如,组合字典中键'apple'的值将是第一个中'apple'值的总和加上第二个中'apple'值的总和等.)
我有以下,但它相当麻烦,需要很长时间才能执行.有没有更简单的方法来实现相同的结果?
comb_dict = {}
for dictionary in list_dictionaries:
for key in dictionary:
comb_dict.setdefault(key, 0)
comb_dict[key] += dictionary[key]
return comb_dict
Run Code Online (Sandbox Code Playgroud)
以下是一些建议的微观基准f2(见下文)可能是一种改进.f2使用iteritems它可以避免在内部循环中进行额外的dict查找:
import collections
import string
import random
def random_dict():
n=random.randint(1,26)
keys=list(string.letters)
random.shuffle(keys)
keys=keys[:n]
values=[random.randint(1,100) for _ in range(n)]
return dict(zip(keys,values))
list_dictionaries=[random_dict() for x in xrange(100)]
def f1(list_dictionaries):
comb_dict = {}
for dictionary in list_dictionaries:
for key in dictionary:
comb_dict.setdefault(key, 0)
comb_dict[key] += dictionary[key]
return comb_dict
def f2(list_dictionaries):
comb_dict = collections.defaultdict(int)
for dictionary in list_dictionaries:
for key,value in dictionary.iteritems():
comb_dict[key] += value
return comb_dict
def union( dict_list ):
all_keys = set()
for d in dict_list:
for k in d:
all_keys.add( k )
for key in all_keys:
yield key, sum( d.get(key,0) for d in dict_list)
def f3(list_dictionaries):
return dict(union( list_dictionaries ))
Run Code Online (Sandbox Code Playgroud)
结果如下:
% python -mtimeit -s"import test" "test.f1(test.list_dictionaries)"
1000 loops, best of 3: 776 usec per loop
% python -mtimeit -s"import test" "test.f2(test.list_dictionaries)"
1000 loops, best of 3: 432 usec per loop
% python -mtimeit -s"import test" "test.f3(test.list_dictionaries)"
100 loops, best of 3: 2.19 msec per loop
Run Code Online (Sandbox Code Playgroud)