具有多种模式的 Python Regex sub()

Question

我想知道是否有任何方法可以组合模式re.sub()而不是使用倍数，如下所示：

import re
s1 = "Please check with the store to confirm holiday hours."
s2 = ''' Hours:
            Monday: 9:30am - 6:00pm
Tuesday: 9:30am - 6:00pm
Wednesday: 9:30am - 6:00pm
Thursday: 9:30am - 6:00pm
Friday: 9:30am - 9:00pm
Saturday: 9:30am - 6:00pm
Sunday: 11:00am - 6:00pm

Please check with the store to confirm holiday hours.'''

strip1 = re.sub(s1, '', s2)
strip2 = re.sub('\t', '', strip1)
print(strip2)

期望的输出：

Hours:
Monday: 9:30am - 6:00pm
Tuesday: 9:30am - 6:00pm
Wednesday: 9:30am - 6:00pm
Thursday: 9:30am - 6:00pm
Friday: 9:30am - 9:00pm
Saturday: 9:30am - 6:00pm
Sunday: 11:00am - 6:00pm

Answer 1

如果您只是想删除特定的子字符串，则可以将模式与交替组合以进行一次删除：

pat1 = r"Please check with the store to confirm holiday hours."
pat2 = r'\t'
combined_pat = r'|'.join((pat1, pat2))
stripped = re.sub(combined_pat, '', s2)

如果“模式”使用实际的正则表达式特殊字符（因为那么您需要担心包装它们以确保在正确的位置交替中断），则更复杂，但对于简单的固定模式，这很简单。

如果您有真正的正则表达式，而不是固定模式，您可能会执行以下操作：

all_pats = [...]
combined_pat = r'|'.join(map(r'(?:{})'.format, all_pats))

所以任何正则表达式特价都保持分组，而不会在交替中“流血”。

Answer 2

你甚至没有使用正则表达式，所以你也可以直接链接replace：

s1 = "Please check with the store to confirm holiday hours."
s2 = ''' Hours:
            Monday: 9:30am - 6:00pm
Tuesday: 9:30am - 6:00pm
Wednesday: 9:30am - 6:00pm
Thursday: 9:30am - 6:00pm
Friday: 9:30am - 9:00pm
Saturday: 9:30am - 6:00pm
Sunday: 11:00am - 6:00pm

Please check with the store to confirm holiday hours.'''

strip2 = s2.replace(s1, "").replace("Hours:","").strip()

print(strip2)