我正在尝试使用cPickle在远程环境中加载该函数.但我收到错误"''模块'对象没有属性......".我真正卡住的地方是名称空间已包含该属性,即使它无法加载请求帮助
import inspect
import cPickle as pickle
from run import run
def get_source(func):
sourcelines = inspect.getsourcelines(func)[0]
sourcelines[0] = sourcelines[0].lstrip()
return "".join(sourcelines)
def fun(f):
return f()
def fun1():
return 10
funcs = (fun, fun1)
sources = [get_source(func) for func in funcs]
funcs_serialized = pickle.dumps((fun.func_name,sources),0)
args_serialized = pickle.dumps(fun1,0)
#Creating the Environment where fun & fun1 doesnot exist
del globals()['fun']
del globals()['fun1']
r = run()
r.work(funcs_serialized,args_serialized)
Run Code Online (Sandbox Code Playgroud)
这是run.py
import cPickle as pickle
class run():
def __init__(self):
pass
def work(self,funcs_serialized,args_serialized):
func, fsources = pickle.loads(funcs_serialized)
fobjs = [compile(fsource, '<string>', 'exec') for fsource in fsources]
#After eval fun and fun1 should be there in globals/locals
for fobj in fobjs:
try:
eval(fobj)
globals().update(locals())
except:
pass
print "Fun1 in Globals: ",globals()['fun1']
print "Fun1 in locals: ",locals()['fun1']
arg = pickle.loads(args_serialized)
Run Code Online (Sandbox Code Playgroud)
错误是
Fun1 in Globals: <function fun1 at 0xb7dae6f4>
Fun1 in locals: <function fun1 at 0xb7dae6f4>
Traceback (most recent call last):
File "fun.py", line 32, in <module>
r.work(funcs_serialized,args_serialized)
File "/home/guest/kathi/python/workspace/run.py", line 23, in work
arg = pickle.loads(args_serialized)
AttributeError: 'module' object has no attribute 'fun1'
Run Code Online (Sandbox Code Playgroud)
Yar*_*riv 11
我发现此链接很有用:http: //stefaanlippens.net/python-pickling-and-dealing-with-attributeerror-module-object-has-no-attribute-thing.html
它提供了两种解决方案 更好的解决方案是添加到加载模块(或__main__)的头部:
from myclassmodule import MyClass
Run Code Online (Sandbox Code Playgroud)
但我认为应该有更好的解决方案.
来自http://docs.python.org/library/pickle.html#what-can-be-pickled-and-unpickled:
请注意,函数(内置和用户定义)由"完全限定"的名称引用而非值引用.这意味着只有函数名称被腌制,以及定义函数的模块名称.函数的代码或其任何函数属性都不会被pickle.因此,定义模块必须可以在unpickling环境中导入,并且模块必须包含命名对象,否则将引发异常.
您在定义fun1的模块中删除了对fun1的引用,因此错误.
| 归档时间: |
|
| 查看次数: |
36678 次 |
| 最近记录: |