我是ASP.NET和C#的新手.我正在尝试从文件夹中检索所有图像并在页面上显示它,但它只选择一个图像.
我的ASP.NET代码:
<form id="form1" runat="server" class="col-lg-5">
<asp:Image ID="Image" runat="server" />
</form>
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我的C#代码:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Web;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Data.SqlClient;
using System.Data;
using System.Configuration;
namespace Blog
{
public partial class index : System.Web.UI.Page
{
SqlConnection con = new SqlConnection(ConfigurationManager.ConnectionStrings["blogconnection"].ToString());
protected void Page_Load(object sender, EventArgs e)
{
con.Open();
string allimage;
string qry="select * from images";
SqlCommand cmd = new SqlCommand(qry, con);
SqlDataReader dr =cmd.ExecuteReader();
if (dr.HasRows)
{
while(dr.Read())
{
if (!string.IsNullOrEmpty(Convert.ToString(dr["Image_Path"])))
{
Image.ImageUrl = Convert.ToString(dr["Image_Path"]);
}
}
}
con.Close();
}
}
}
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我想要的是: 我想选择所有在sql表中存储路径的图像.
附加:有没有办法从文件夹中选择路径存储在sql中的视频,意思是选择不同文件夹中的视频和图像,并按指定日期或最新上传等显示在同一页面上.
任何帮助将不胜感激.
编辑#1
在PHP中我使用下面的代码来获取所有图像并显示它,是否有任何东西相当于ASP.NET中的下面的代码?
PHP代码
<?php
include 'conn.php';
$smt=$conn->prepare('SELECT * FROM post');
$smt->execute();
?>
<?php include 'header.php';
?>
<div class="">
<?php
if(isset($_SESSION['user']))
{
include 'nav.php';
}
else
{
include 'nav-simple.php';
}
?>
<?php include 'slider.php';?>
<?php include 'right_sidebar.php';?>
<div class="col-md-1 top_space"></div>
<div class="container col-md-8 main-container-top">
<br/>
<div class="">
<?php while ($gdata = $smt->fetch(PDO::FETCH_OBJ)): ?>
<a href="#" class="col-md-4"><img src="posts/<?php echo $gdata->Post_Path; ?>" alt="image" class="post-image"/></a>
<div class="media-body col-md-8 post pull-left">
<div class="post-overview">
<ul>
<li class="post-category"><?php echo $gdata->Category; ?></li>
<li class="post-timestemp">Post on <?php echo $gdata->Post_Date; ?></li>
</ul>
<a href="post-description.php?id=<?php echo $gdata->Id ?>"><h4
class="media-heading h4"><?php echo $gdata->Title; ?></h4></a>
<p class="post-text"><?php echo $gdata->Post; ?></p><br/>
</div>
</div>
<div class="post-image-space"></div>
<?php endwhile;?>
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在后面的代码编写Collection()方法来检索图像作为一个List的Strings这样的(而且最好是用Using语句):
protected IEnumerable<string> Collection()
{
string address = ConfigurationManager.ConnectionStrings["blogconnection"].ToString();
using (SqlConnection con = new SqlConnection(address))
{
con.Open();
string qry = "select * from images";
SqlCommand cmd = new SqlCommand(qry, con);
using (SqlDataReader dr = cmd.ExecuteReader())
{
if (!dr.HasRows) return allimage;
while (dr.Read())
{
if (!string.IsNullOrEmpty(Convert.ToString(dr["Image_Path"])))
{
yield return (dr["Image_Path"].ToString());
}
}
}
}
}
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然后你可以这样使用asp:Repeater:
<asp:Repeater ID="Repeater1" runat="server" DataSourceID="imgCats">
<ItemTemplate>
<div>
<img src='<%# Container.DataItem.ToString() %>' alt="" />
</div>
</ItemTemplate>
</asp:Repeater>
<asp:ObjectDataSource ID="imgCats" runat="server" SelectMethod="Collection"
TypeName="WebApplication1.WebForm8">
</asp:ObjectDataSource>
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或者你可以这样做:
<form id="form1" runat="server" class="col-lg-5">
<div>
<ul>
<% var drc = Collection();
foreach (var item in drc)
{ %>
<li>
<img src="<%: item %>"/>
</li>
<% } %>
</ul>
</div>
</form>
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您可以动态地将新的 asp:image 对象添加到 form1。
Image img = new Image();
img.ImageUrl = dr["Image_Path"].ToString();
img.AlternateText = "Test image";
form1.Controls.Add(img);
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