基于多个键/值对的自定义排序哈希数组

Question

我有一个哈希数组,我需要根据两个不同的键值对进行排序.

这是我要排序的数组:

array_group =  [
 {operator: OR, name: "some string", status: false},
 {operator: AND, name: "other string", status: false},
 {operator: _NOT_PRESENT, name: "another string", status: true},
 {operator: AND, name: "just string", status: true}
]

我想排序array_group所以我有status: true第一个项目,然后是status: false,然后是项目,operator: _NOT_PRESENT最后根据名称对其进行排序,结果如下:

array_group = [
 {operator: AND, name: "just string", status: true},
 {operator: AND, name: "other string", status: false},
 {operator: OR, name: "some string", status: false},
 {operator: _NOT_PRESENT, name: "another string", status: true},
]

有没有办法可以在不创建子数组并对其进行排序并将它们连接起来的情况下完成此操作？

Answer 1

您还可以使用Enumerable#sort_by.该示例构建一个数组,在排序时逐个元素进行比较.

array_group.sort_by { |e| [e[:operator] == "_NOT_PRESENT" ? 1 : 0, 
                           e[:status] ? 0 : 1, 
                           e[:name]] }

上面的例子operator: "_NOT_PRESENT"也用by 命令记录:status.以下代码段精确地执行了问题的排序.

def priority(h)
  case
  when h[:operator] == "_NOT_PRESENT" then 3
  when h[:status] == false            then 2
  # h[:status] == true
  else 1
  end
end

array_group.sort_by { |e| [priority(e), e[:name]] }