DRY - 将一定数量的元素添加到数组的末尾,直到它的计数达到特定的int

Question

由于我正在使用一个相当古老的库,我需要将数组块分成五个块.所以,如果我的数组有9个元素,我需要将它组合起来(5和4)然后我需要在最后一个数组中添加一个空元素以使其达到5.

我写了一些非常糟糕的代码,但是我知道这是违反DRY原则的,因为它计算了数字,并使用多个if语句来推送正确数量的空白元素以重新获得5.

谁能告诉我如何我这样应该向下突破该代码$chunkFive被array_push编到,直到它有5个元素呢？

$blank = array("","","blank-image.png","",""); // create the blank image array
if(count($chunkFive) < 5){
    echo 'it contains less than five elements';
    if(count($chunkFive) == 4){
        echo 'insert one element'; // 4 present + array_push 1 = 5
        array_push($chunkFive,$blank);
    }else if(count($chunkFive) == 3){
        echo 'insert two elements'; // 3 present + array_push 2 = 5
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
    }else if(count($chunkFive) == 2){
        echo 'insert three elements'; // 2 present + array_push 3 = 5
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
    }else if(count($chunkFive) == 1){
        echo 'insert four elements';  // 1 present + array_push 4 = 5
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
        array_push($chunkFive,$blank);
    }
}else{
    echo 'it contains five elements'; // no need to adjust
    // do nothing
}

Answer 1

用途array_pad:

array_pad($chunkFive, 5, $blank);

例如:

[20] boris> $blank = ''; // easier to read ;-)
// ''
[21] boris> array_pad(array("one"), 5, $blank);
// array(
//   0 => 'one',
//   1 => '',
//   2 => '',
//   3 => '',
//   4 => ''
// )
[22] boris> 

该函数自php 4以来一直存在 - 使用内置函数通常是值得的,因为它们在大多数情况下都是优化的c实现.