在继续之前等待在Java Swing中按下按钮？

Question

所以我有这个GUI

public ChangePokemonView(Controller c)
{
    this.controller = c;
    this.currentBattleEnvironment = currentBattleEnvironment.getInstance();
    populateInactivePokemon(); //REMOVE LATER REMOVE LATER  REMOVE LATER  REMOVE LATER  REMOVE LATER 
    this.pokemonList = new JList(inactivePlayerPokemon);
    pokemonList.setSelectionMode(ListSelectionModel.SINGLE_SELECTION); //Only one thing can be selected at a time.
    this.pokemonLabel = new JLabel("Choose your Pokemon!");
    this.confirmSelection = new JButton("Confirm Selection");
    this.confirmSelection.addActionListener(this);

    setLayout(new BorderLayout());
    setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); //Closes GUI window when close, may need to change later
    JPanel centerPanel = new JPanel(new GridLayout(3, 1));
    centerPanel.add(pokemonLabel);
    centerPanel.add(pokemonList);
    centerPanel.add(confirmSelection);

    add("Center", centerPanel);
    pack();
    setVisible(true);
}

这只是创建一个项目列表和一个按钮.单击该按钮时,它将获取所选项目并将其返回到控制器然后进行处理(对于我们的项目,它会更改玩家口袋妖怪).

 */
@Override
public void actionPerformed(ActionEvent event)
{
    if (event.getSource() == confirmSelection)
    {
        this.pokemonSelected = (String) pokemonList.getSelectedValue();
        this.controller.setCurrentPokemon(this.pokemonSelected);
        //JOptionPane.showConfirmDialog(null, "You pressed: "+output); //USED FOR TESTING, THIS WILL OUPUT JUST THE NAME THAT WAS SELECTED
    }

}

setCurrentPokemon与控制器没有任何关系.我只是想确保它现在能够得到选择.但是我在等待选择的其余代码时遇到问题.

我认为Swing和Java的输入应该暂停并等待输入,然后继续使用其余的代码.但是,现在它运行打开选择菜单,但然后在控制器中将选定的宠物小猫设置为null.我想添加一个while循环来等待并解决这个问题,但我觉得有一个更容易的方法来构建Swing.

有没有办法,所以我可以让我的其余代码等到选择按钮并处理操作？

提前致谢.

Answer 1

用一个JOptionPane.它将为您构建模态对话框和按钮.模态对话框将停止执行,直到关闭为止.

有关更多信息和工作示例,请阅读有关如何创建对话框的Swing教程中的部分.

add("Center", centerPanel);

不要使用"魔法"值.API将定义应使用的值.这也不是向Container添加组件的方法.相反,你应该使用:

add(centerPanel, BorderLayout.CENTER);