使用GoogleMap BitmapDescriptor的VectorDrawable

Question

我BitmapDescriptor在创建MarkerOptions使用VectorDrawableAPI 5.0+的图标时遇到谷歌地图问题

用于创建的方法:

@NonNull
private BitmapDescriptor getBitmapDescriptor(int id) {
    return BitmapDescriptorFactory.fromResource(id);
}

当id参数包含png drawable时,一切都很好,但是如果我VectorDrawable在xml中定义它,那么当googleMap.addMarker(marker)(BitmapDescriptor不是null)时,App总会崩溃.

11-05 10:15:05.213 14536-14536/xxx.xxxxx.app E/AndroidRuntime: FATAL EXCEPTION: main
    Process: xxx.xxxxx.app, PID: 14536
    java.lang.NullPointerException
        at com.google.a.a.ae.a(Unknown Source)
        at com.google.maps.api.android.lib6.d.dn.<init>(Unknown Source)
        at com.google.maps.api.android.lib6.d.dm.a(Unknown Source)
        at com.google.maps.api.android.lib6.d.ag.<init>(Unknown Source)
        at com.google.maps.api.android.lib6.d.eu.a(Unknown Source)
        at com.google.android.gms.maps.internal.j.onTransact(SourceFile:167)
        at android.os.Binder.transact(Binder.java:380)
        at com.google.android.gms.maps.internal.IGoogleMapDelegate$zza$zza.addMarker(Unknown Source)
        at com.google.android.gms.maps.GoogleMap.addMarker(Unknown Source)
        at xxx.xxxxx.app.ui.details.DetailActivity.lambda$initGoogleMaps$23(DetailActivity.java:387)
        at xxx.xxxxx.app.ui.details.DetailActivity.access$lambda$10(DetailActivity.java)
        at xxx.xxxxx.app.ui.details.DetailActivity$$Lambda$13.onMapReady(Unknown Source)
        at com.google.android.gms.maps.SupportMapFragment$zza$1.zza(Unknown Source)
        at com.google.android.gms.maps.internal.zzl$zza.onTransact(Unknown Source)
        at android.os.Binder.transact(Binder.java:380)
        at com.google.android.gms.maps.internal.av.a(SourceFile:82)
        at com.google.maps.api.android.lib6.d.fa.run(Unknown Source)
        at android.os.Handler.handleCallback(Handler.java:739)
        at android.os.Handler.dispatchMessage(Handler.java:95)
        at android.os.Looper.loop(Looper.java:135)
        at android.app.ActivityThread.main(ActivityThread.java:5221)
        at java.lang.reflect.Method.invoke(Native Method)
        at java.lang.reflect.Method.invoke(Method.java:372)
        at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:899)
        at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:694)

无论我如何检索drawable,尝试使用BitmapFactory.fromResources以后创建位图,BitmapDescritpionFactory.fromBitmap但结果是相同的.它只适用于矢量drawable.尝试了不同的向量,但似乎矢量复杂性不是问题.

有谁知道如何修复此崩溃？

@编辑

似乎问题不在于BitmapDescriptior它本身,而在于加载VectorDrawable错误的位图.然而,答案中提出的解决方案仍然很好.

Answer 1

可能的解决方法:

private BitmapDescriptor getBitmapDescriptor(int id) {
    Drawable vectorDrawable = context.getDrawable(id);
    int h = ((int) Utils.convertDpToPixel(42, context));
    int w = ((int) Utils.convertDpToPixel(25, context));
    vectorDrawable.setBounds(0, 0, w, h);
    Bitmap bm = Bitmap.createBitmap(w, h, Bitmap.Config.ARGB_8888);
    Canvas canvas = new Canvas(bm);
    vectorDrawable.draw(canvas);
    return BitmapDescriptorFactory.fromBitmap(bm);
}

Answer 2

根据bug报告(由vaughandroid发布 - 谢谢!)暂时不支持使用VectorDrawable.有关详细信息,请参阅错误报告中的注释.

以下是Google地图团队建议的解决方法:

/**
 * Demonstrates converting a {@link Drawable} to a {@link BitmapDescriptor},
 * for use as a marker icon.
 */
private BitmapDescriptor vectorToBitmap(@DrawableRes int id, @ColorInt int color) {
    Drawable vectorDrawable = ResourcesCompat.getDrawable(getResources(), id, null);
    Bitmap bitmap = Bitmap.createBitmap(vectorDrawable.getIntrinsicWidth(),
            vectorDrawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
    Canvas canvas = new Canvas(bitmap);
    vectorDrawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
    DrawableCompat.setTint(vectorDrawable, color);
    vectorDrawable.draw(canvas);
    return BitmapDescriptorFactory.fromBitmap(bitmap);
}

用这种方式:

// Vector drawable resource as a marker icon.
    mMap.addMarker(new MarkerOptions()
            .position(ALICE_SPRINGS)
            .icon(vectorToBitmap(R.drawable.ic_android, Color.parseColor("#A4C639")))
            .title("Alice Springs"));

着色的矢量是一个奖励

Answer 3

或者你可以简单地使用Android KTX

例如：

val markerBitmap = ResourcesCompat.getDrawable(resources, R.drawable.ic_marker, null)?.toBitmap()
val icon = BitmapDescriptorFactory.fromBitmap(markerBitmap)
val marker = MarkerOptions().icon(icon)

参考： .toBitmap()

Answer 4

这是另一个参考:http: //qiita.com/konifar/items/aaff934edbf44e39b04a

public class ResourceUtil {

@TargetApi(Build.VERSION_CODES.LOLLIPOP)
private static Bitmap getBitmap(VectorDrawable vectorDrawable) {
    Bitmap bitmap = Bitmap.createBitmap(vectorDrawable.getIntrinsicWidth(),
            vectorDrawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
    Canvas canvas = new Canvas(bitmap);
    vectorDrawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
    vectorDrawable.draw(canvas);
    return bitmap;
}

private static Bitmap getBitmap(VectorDrawableCompat vectorDrawable) {
    Bitmap bitmap = Bitmap.createBitmap(vectorDrawable.getIntrinsicWidth(),
            vectorDrawable.getIntrinsicHeight(), Bitmap.Config.ARGB_8888);
    Canvas canvas = new Canvas(bitmap);
    vectorDrawable.setBounds(0, 0, canvas.getWidth(), canvas.getHeight());
    vectorDrawable.draw(canvas);
    return bitmap;
}

public static Bitmap getBitmap(Context context, @DrawableRes int drawableResId) {
    Drawable drawable = ContextCompat.getDrawable(context, drawableResId);
    if (drawable instanceof BitmapDrawable) {
        return ((BitmapDrawable) drawable).getBitmap();
    } else if (drawable instanceof VectorDrawableCompat) {
        return getBitmap((VectorDrawableCompat) drawable);
    } else if (drawable instanceof VectorDrawable) {
        return getBitmap((VectorDrawable) drawable);
    } else {
        throw new IllegalArgumentException("Unsupported drawable type");
    }
}
}