Java XPath获取具有与特定文本匹配的特定标记的所有节点

Question

我有以下常规XML文件:

<root>
    <Items>
        <Item>
            <tag1>text1</tag1>
            <tag2>text2</tag2>
            <tag3>text3</tag3>
        </Item>
        <Item>
            <tag1>text1</tag1>
            <tag2>text4</tag2>
            <tag3>text5</tag3>
        </Item>
    </Items>
</root>

我希望得到文本等于的所有节点(全部<Item>),然后打印所有其他标签,例如.<tag1>text1<tag2>

我从这开始,但努力寻找TODO'S的答案:

try {
    DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
    DocumentBuilder builder = factory.newDocumentBuilder();
    Document doc = builder.parse(("\URI\file.xml"));
    XPathFactory xPathfactory = XPathFactory.newInstance();
    XPath xpath = xPathfactory.newXPath();
    //TODO: Is this correct query?
    XPathExpression expr = xpath.compile("//root//Items//Item//tag1[contains(., 'text1')]");
    NodeList nl = (NodeList) expr.evaluate(doc, XPathConstants.NODESET);
    for (int i=0; i<nl.getLength(); i++) {
        //TODO: How to iterate over all matched <Item> and get their <tag2>, <tag3> etc.?
    }
} catch (Exception e) {e.printStackTrace();}

谢谢,

Answer 1

您可以使用Chrome开发者工具$x("path")功能来测试XPath.这真的很容易.它也适用于最新的Firefox.

我使用您提供的文本制作了一个HTML文件,然后在Chrome中打开它.在控制台中,键入$x("/some-path")以测试内容.

1. 获取物品:

   //Item
   

2. 其中tag1文本等于text1:

   //Item/tag1[.='text1']
   

3. 获取以下作为tag2的兄弟:

   //Item/tag1[.='text1']/following-sibling::tag2
   

如果你想要Item而不是tag2:

//Item[ ./tag1[.='text1']/following-sibling::tag2 ]